3 years ago

Please Help <3 Please Help <3

1 answer:

8 0

$f(x)=\dfrac{x}{2}-3,\ g(x)=3x^2+x-6\\\\(f+g)(x)=f(x)+g(x)=\left(\dfrac{x}{2}-3\right)+(3x^2+x-6)=\dfrac{1}{2}x-3+3x^2+x-6\\\\=3x^2+1\dfrac{1}{2}x-9$

$Answer:\ \boxed{B.\ 3x^2+\dfrac{3}{2}x-9}}$

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