Please Help <3 Please Help <3

Mathematics

1 answer:

Ne4ueva [31]3 years ago

8 0

$f(x)=\dfrac{x}{2}-3,\ g(x)=3x^2+x-6\\\\(f+g)(x)=f(x)+g(x)=\left(\dfrac{x}{2}-3\right)+(3x^2+x-6)=\dfrac{1}{2}x-3+3x^2+x-6\\\\=3x^2+1\dfrac{1}{2}x-9$

$Answer:\ \boxed{B.\ 3x^2+\dfrac{3}{2}x-9}}$

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The sum of the measures of two angles is 180 degrees. One angle measures 3a and the other angle measures 2a-25 Find a. Then find

e-lub [12.9K]

The sum of the angles equal 180 degrees, so we plug the angle values into an equation:
3a + 2a - 25 = 180.
By combining like terms, this becomes:
5a - 25 = 180
Now, if we add 25 to both sides to isolate a, we get:
5a = 205
Finally, we need to divide both sides by 5 to find a, and we get:
a = 41

Yay! Now we have a. Now we just plug them into the original values! So:
2(41) - 25
Multiply out:
82 - 25
The first angle is equal to 57.

Then we use the second angle:
3(41)
Multiply out:
123
The second angle is equal to 123.

Hope this helps!
~Chrys

8 0

4 years ago

Tyler reasoned "9/25 is equivalent to 18/50 and to 36/100, so the decimal of 9/25 is 0.36" Use long division to decide if Tyler

Sedbober [7]

He statement is true 9/25=0.36

6 0

3 years ago

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