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Anarel [89]
3 years ago
6

Solve for x and y simultaneous3x - 5y = 3y-2x = 5​

Mathematics
1 answer:
timurjin [86]3 years ago
7 0

Answer:

the answer is x= -4 and y= -3

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What is the equation of a parabola in vertex form for a line that passed through (5,-4) and has vertex (-2,5)
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\text{The vertex form of a parabola}\\\\y=a(x-h)^2+k\\\\\text{We have the vertex}\ (-2,\ 5)\to h=-2,\ k=5.\\\\\text{Substitute}\\\\y=a(x-(-2))^2+5=a(x+2)^2+5\\\\\text{We have the point}\ (5,\ -4).\\\text{Substitute the coordinates of the point to the equation:}\\\\-4=a(5+2)^2+5\\\\-4=a(7)^2+5\\\\-4=49a+5\qquad|-5\\\\-9=49a\qquad|:49\\\\a=-\dfrac{9}{49}\\\\Answer:\ \boxed{y=-\dfrac{9}{49}(x+2)^2+5}

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cestrela7 [59]
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2 questions here:
solmaris [256]
<span>1. Make y the subject 
a) 4y=12x+18
y = 3x + 4.5

b) 2x=7-3y
3y = -2x + 7
y = -2/3x + 7/3

2.
a) what is the equation of the line which passes through both (-2,-4) and (6,16)

slope = (16 + 4)/(6 +2) = 20/8 = 2.5
y = mx + b
-4 =2.5(-2) +b
-4 = -5 +b
b = 1

equation
y = 2.5x + 1


b) what is the equation of the line perpendicular to y= 1/2X + 7 passing through point (3,9)

</span>y= 1/2X + 7
slope = 1/2

slope of line perpendicular = -2

passing through point (3,9)

y = mx + b
9 = -2 (3) + b
b = 15

equation

y = -2x + 15

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4 years ago
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