Assume that A varies directly with z. If A = 30 when z = 5, find A when z = 9.
2 answers:
We can this two ways:
1) If A = 30 when Z = 5, then A = 6Z or A = 6*z
So if Z = 9, 9 * 6 = 54. A = 54.
2) You can set up a proportion:
where x = the unknown A-value.
Crossmultiply:
5x = 30*9
5x = 270
Divide by 5 on both sides to isolate the variable
x = 54
54 is your A value when Z = 9.
Either way you solve it, your answer is 54.
1) If A = 30 when Z = 5, then A = 6Z or A = 6*z
So if Z = 9, 9 * 6 = 54. A = 54.
2) You can set up a proportion:
Crossmultiply:
5x = 30*9
5x = 270
Divide by 5 on both sides to isolate the variable
x = 54
54 is your A value when Z = 9.
Either way you solve it, your answer is 54.
You might be interested in
Answer:
<em>The correct option is: 11.5</em>
Step-by-step explanation:
Suppose, the length of the unknown side is
So, here the length of hypotenuse is 14 and the lengths of other two sides are 8 and .
As the given triangle is right angle triangle, so <u>using Pythagorean theorem</u>, we will get.........
<em>(Rounded to the nearest tenth)</em>
So, the length of the unknown side is 11.5
Answer:
- If the sum is 6, a small cone will be ordered.
- If the sum is 8 or 9, a medium cone will be ordered.
- If the sum is 11, a large cone will be ordered.
Step-by-step explanation:
The table below shows the possible outcomes from drawing two balls. We see the relative frequencies to be ...
6: 4
8: 2
9: 2
11: 4
To make a fair decision, we want the relative frequencies of the decision possibilities to be the same. If we combine sums 8 and 9 to one category (medium cone, for example), then 6, (8 or 9), and 11 will all have the same relative frequency: 4.
The appropriate "fair decision" choice is ...
6: small cone
8 or 9: medium cone
11: large cone
