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bagirrra123 [75]
3 years ago
15

12 + x to the power of 4 - 6 when x = 8

Mathematics
1 answer:
iren [92.7K]3 years ago
8 0

value of  12+x^4-6 at x=8 is  5002 .

<u>Step-by-step explanation:</u>

here we need to evaluate 12 + x to the power of 4 - 6 when x = 8 or , 12+x^4-6 where x=8 . Let's find out:

⇒ 12+x^4-6

Putting x =8 :

⇒ 12+8^4-6

Splitting 8 to power 4 into 8 to power 2 ( 2 times )

⇒ 12+8^2(8^2)-6

⇒ 12+64(64)-6

⇒ 12+4096-6

⇒ 4096+6

⇒ 5002

Therefore , value of  12+x^4-6 at x=8 is  5002 .

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The image of F(-5,-9) after translating along &lt;4, 6 &gt; and then translating along &lt; 3, 5&gt; is? F’(?,?)
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<h3>Answer:  (2, 2)</h3>

==============================================

Explanation:

The phrasing "translated along <4,6>" is another way of saying "shift 4 to the right, shift 6 up"

In general, "translated along <m,n>" is the same as writing (x,y) \to (x+m, y+n). If m is positive, then we shift m units to the right. If m is negative, then we shift to the left. The same story happens with the n, but we focus on the y coordinate.

-------------

With all that in mind, starting at F(-5,-9) and translating along <4,6> has us arrive at (-1, -3). Add 4 to the x coordinate and add 6 to the y coordinate.

We can say

(x,y) \to (x+4,y+6)\\\\(-5,-9) \to (-5+4,-9+6)\\\\(-5,-9) \to (-1,-3)\\\\

Showing that (-5,-9) moves to (-1,-3)

This is after the first translation, but there's a second translation.

We'll apply the same idea, but different numbers this time

(x,y) \to (x+3,y+5)\\\\(-1,-3) \to (-1+3,-3+5)\\\\(-1,-3) \to (2,2)\\\\

So (-1,-3) moves to (2,2)

Overall we have

  • (-5,-9) move to (-1,-3) after the first translation
  • (-1,-3) move to (2,2) after the second translation

Therefore, the original point ends up at (2,2) which is the final answer

--------------

Extra info:

A nice shortcut is that the vectors <4,6> and <3,5> can be added to get <4+3,6+5> = <7,11>. So overall, we're shifting 7 units to the right and 11 units up when we combine the two translation vectors.

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