A cube-shaped satellite has side lengths of 10 centimeters. What is the least amount of aluminum needed to cover the satellite?

Mathematics

1 answer:

Rudiy274 years ago

5 0

Answer:

600 square centimeter.

Step-by-step explanation:

A cube-shaped satellite has side lengths of 10 centimeters.

So, the total surface area of the satellite is 2(10 × 10 + 10 × 10 + 10 × 10) = 600 sq. cm.

{The total surface area of a cuboid having length L, width W, and height H is given by 2(LW + WH + HL)}

Therefore, the least amount of aluminum needed to cover the satellite will be 600 sq. cm. (Answer)

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