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RoseWind [281]
3 years ago
10

What is the answer to 4x + 3x

Mathematics
1 answer:
viva [34]3 years ago
6 0

Answer: sorry I font know

Step-by-step explanation:but I need points

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A six-week fitness program was designed to decrease the time it takes retired individuals to walk one mile. At the beginning of
valkas [14]

Answer:

c. The sampling distribution of the sample means can be assumed to be approximately normal because the distribution of the sample data is not skewed

Step-by-step explanation:

From the given data, we have;

The category of the sample = Retired individuals

The number of participants in the sample = 20

The duration of program = six-weeks

The improvement seen by most participants = Little to no improvement

The improvement seen by few participants = Drastic improvement

Therefore, given that the participants are randomly selected and the majority of the participants make the same observation of improvement in the time to walk a mile, we have that, the majority of the outcomes show little difference in walk times after the program, therefore, the distribution of the sample data is not skewed and can be assumed to be approximately normal

7 0
3 years ago
Please help me answer <br> 70 is 160% of what?
Lina20 [59]
You are basically asking 160% of X = 70. 
1) 70 x 100 = 7000 (to turn the 70 into a %)
2) 7000 /160 = 43.75

You can reverse the equation to double check the answer. 
160% x 43.75 = 70
6 0
3 years ago
Read 2 more answers
Which expressions show how 8 • 54 can be rewritten using the distributive property? Choose all answers that are correct.
irga5000 [103]
Answer choice B is using the distributive property.
6 0
3 years ago
GEOMETRY <br> please Help
geniusboy [140]

Answer:

A right circular cone

Step-by-step explanation:

7 0
3 years ago
Find the volume of a right circular cone that has a height of 6.7 in and a base with a diameter of 8.8 in. Round your answer to
N76 [4]

Answer: 135.8

Step-by-step explanation:

the formula for this is πr²H/3

π4.4^2x6.7/3

407.5/3

135.8

4 0
3 years ago
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