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kodGreya [7K]
3 years ago
12

PleAse help and show how you got it if you don’t mind

Mathematics
1 answer:
Lorico [155]3 years ago
3 0
1)

\bf \textit{surface area of a cube}\\\\
s=6x^2\quad 
\begin{cases}
x=\textit{length of a side}\\
---------\\
s=150
\end{cases}\implies 150=6x^2\implies \cfrac{150}{6}=x^2
\\\\\\
25=x^2\implies \sqrt{25}=x\implies \boxed{5=x}

3)

\bf \textit{volume of a square pyramid}\\\\
V=\cfrac{b^2h}{3}\quad 
\begin{cases}
b=\textit{base's side}\\
h=height\\
-------\\
h=3\\
V=25
\end{cases}\implies 25=\cfrac{b^2\cdot 3}{3}\implies 25=b^2\cdot \cfrac{3}{3}
\\\\\\
25=b^2\cdot 1\implies 25=b^2\implies \sqrt{25}=b\implies \boxed{5=b}
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Answer:

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Step-by-step explanation:

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(y – y₁) = m(x – x₁), where m is the slope (2) and (x₁, y₁) is the point the line passes through (3,3).  

Therefore:  

(y – 3) = 2 (x – 3)

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3 years ago
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Alenkinab [10]

Answer:

Maximum: 1, Minimum: -3, Midline y = -1, Amplitude = 4, Period = \pi, Frequency \displaystyle =\frac{1}{\pi},  equation : f(x)=-4cos(2x)+1

Step-by-step explanation:

<u>Sinusoid Functions</u>

It refers to the oscillating functions like the sine or cosine which range from a minimum and maximum value periodically.

The graph shown can give us all the information we need to answer these questions:

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jok3333 [9.3K]

Answer:

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