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kodGreya [7K]
3 years ago
12

PleAse help and show how you got it if you don’t mind

Mathematics
1 answer:
Lorico [155]3 years ago
3 0
1)

\bf \textit{surface area of a cube}\\\\
s=6x^2\quad 
\begin{cases}
x=\textit{length of a side}\\
---------\\
s=150
\end{cases}\implies 150=6x^2\implies \cfrac{150}{6}=x^2
\\\\\\
25=x^2\implies \sqrt{25}=x\implies \boxed{5=x}

3)

\bf \textit{volume of a square pyramid}\\\\
V=\cfrac{b^2h}{3}\quad 
\begin{cases}
b=\textit{base's side}\\
h=height\\
-------\\
h=3\\
V=25
\end{cases}\implies 25=\cfrac{b^2\cdot 3}{3}\implies 25=b^2\cdot \cfrac{3}{3}
\\\\\\
25=b^2\cdot 1\implies 25=b^2\implies \sqrt{25}=b\implies \boxed{5=b}
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Answer:

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Step-by-step explanation:

Given

(81x^4y^{16})^{\frac{1}{2}}

Required

Determine an equivalent expression

Express 81 as 9^2

(9^2x^4y^{16})^{\frac{1}{2}}

Apply law of indices

9^2^{\frac{1}{2}} * x^4^{\frac{1}{2}} * y^{16}^{\frac{1}{2}}

9^{\frac{2*1}{2}} * x^{\frac{4*1}{2}} * y^{\frac{16*1}{2}}

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