Answer:
No
Step-by-step explanation:
For a point to be the midpoint of a line segment, it must bisect it into two equal segments and be on the line segment (hence, colinear with the endpoints). All four B points are equidistant from points A and C, but aren’t colinear with A and C. Therefore, they aren’t all midpoints of line segment AC.
I hope this helps! :)
1. 3x-6+2x+108+88=360
5x=170
x=34
2. figure B
An= mth term.
an=a₁+(n-1)*d
a₁₂=41
a₁₅=140
a₁₂=41
41=a₁+(12-1)*d
41=a₁+11d
a₁+11d=41 (1)
a₁₅=140
140=a₁+(15-1)*d
140=a₁+14d
a₁+14d=140 (2)
With the equiations (1) and (2) build a system of equations
a₁+11d=41
a₁+14d=140
we solve it.
-(a₁+11d=41)
a₁+14d=140
--------------------
3d=99 ⇒d=99/3=33
a₁+11d=41
a₁+(11*33)=41
a₁+363=41
a₁=41-363=-322
an=a₁+(n-1)*d
an=-322+(n-1)*33
an=-322+33n-33
an=-355+33n
an=-355+33n
To check:
a₁₂=-355+33*12=-355+396=41
a₁₅=-355+33*15=-355+495=140.
You want to compare the square root of 55 using "mental math". Start off by choosing two perfect squares that you can think of that are close to 55.
If you don't know perfect squares then start with the number 2 and multiply it by itself. 2 times 2 equals 4, so 4 is a perfect square.
Take the number 3, multiply it by itself, and so on. Do this for all the numbers until you find two perfect squares that are close to 55.
The two perfect squares closest to 55 are the square roots of 49 and 64. Find the square root of these numbers.
√49 = 7
√64 = 8
Calculate how far 55 is from 49 and 64. 55 is 6 digits away from 49 and 9 digits away from 64.
This means the square root of 55 will be closer to the square root of 49; 7. Since we know that it will be closer to 7, you can put the less than sign for your answer.
√55 < 7.7
(The actual square root of 55 is ~7.4, so we were correct in determining the answer without using a calculator!)
Area = πr²
50 = πr²
r = √50/π
so diameter = 2√50/π
which is = 7.98m to 3sf
