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4 years ago

Help solving the problem for number 1-3

Mathematics

1 answer:

lbvjy [14]4 years ago

8 0

1. 4 boxes for 12.....12/4 = 3...paid 3 per box
if 6 were bought....6 * 3 = 18 bucks would be spent

2. 2/9 of 36..." of " means multiply
2/9 * 36 = 72/9 = 8 expected to forget their bows

3. 8 packs for 32.....32/8 = 4 per pack
if 14 packs were bought.....14 * 4 = 56 bucks would be spent

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4. Which ordered pair is a solution of 3y + 2 = 2x - 5?

Lyrx [107]

Answer:

we determine that none of the ordered pair is a solution of $3y\:+\:2\:=\:2x\:-\:5$ as none of the ordered pairs satisfy the equation.

Step-by-step explanation:

Considering the equation

$3y\:+\:2\:=\:2x\:-\:5$

Putting (-5,2) in the equation

$3y\:+\:2\:=\:2x\:-\:5$

$3\left(2\right)\:+\:2\:=\:2\left(-5\right)\:-\:5$

$8=-15$ ∵ L.H.S ≠ R.H.S

FALSE

Putting (0,-5) in the equation

$3y\:+\:2\:=\:2x\:-\:5$

$3\left(-5\right)\:+\:2\:=\:2\left(0\right)\:-\:5$

$-13=-5$ ∵ L.H.S ≠ R.H.S

FALSE

Putting (5,1) in the equation

$3y\:+\:2\:=\:2x\:-\:5$

$3\left(1\right)+\:2\:=\:2\left(5\right)-\:5$

$5\:=-5$ ∵ L.H.S ≠ R.H.S

FALSE

Putting (7,5) in the equation

$3y\:+\:2\:=\:2x\:-\:5$

$3\left(5\right)+\:2\:=\:2\left(7\right)-\:5\:\:$

$17=9$ ∵ L.H.S ≠ R.H.S

FALSE

From the above calculations, we determine that none of the ordered pair is a solution of $3y\:+\:2\:=\:2x\:-\:5$ as none of the ordered pairs satisfy the equation.

4 0

3 years ago

Need help, please<br> will give brainly

jeka57 [31]

Answer:

it's J

Step-by-step explanation

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4 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=simplify%20%5Csqrt%7B21%20-%2020i%7D%20" id="TexFormula1" title="simplify \sqrt{21 - 20i} " al

Valentin [98]

Answer:

o. k this is a required answere

6 0

3 years ago

10. An arithmetic sequence has this recursive formula. What is the explicit formula?

Mrrafil [7]

Answer:

$a_{n}=45-3n$

Step-by-step explanation:

Method 1:

Arithmetic sequence is in the form

$a_{n} =a_{1} +(n-1)d\\$

d is the common difference, can be found by:

$d=a_{n}-a_{n-1}=-3$

Subtituting the $a_{1}$ and $d$

You get:

$a_{n}=42+(-3)(n-1)=45-3n$

Method 2 (Mathematical induction):

Assume it is in form $a_{n}=45-3n$

Base step: $a_{1} =45-3(1)=42$

Inducive hypophesis: $a_{n}=45-3n$

GIven: $a_{n+1} =a_{n}-3$

$a_{n+1}=45-3n-3=45-3(n+1)$

Proved by mathematical induction

$a_{n}=45-3n$

5 0

3 years ago

Please help❤️❤️ It’s for 20 pts!!

solong [7]

If you need part A, draw a person and label them 6 feet tall and a shadow coming off of him that is five feet long and draw a basketball hoop that and label it X feet tall and draw a shadow coming from it that is 8 feet long. To solve, you use proportions 6/5=X/8 solving this you get X=9.6 feet which is the height of the rim. Therefore, the rim does not meet regulation height, since the required height (10 feet) is greater than the actual height (9.6 feet).

4 0

3 years ago