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Serhud [2]
3 years ago
15

Please can you tell me if it is Complementary, supplementary, or neither. also what is "x"

Mathematics
2 answers:
MakcuM [25]3 years ago
8 0
It is supplementary angle
(3X+25)+(2x)=180
5x+25=180
-25. -25
5x=155
/5. /5
X=31
Sloan [31]3 years ago
4 0
Supplementary, because both of the measurements are on a straight line which is equal to 80 degrees and x is equal too 31
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Select the action you would use to solve 3x = 12. Then select the property
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Answer:

C: Divide both sides by 3

F: Division property of equality

Step-by-step explanation:

3x=12\\x=\frac{12}{3}\\x=4

3 0
2 years ago
Find the value of each variable. If you give the decimal value, round to the nearest tenth.
DiKsa [7]

u = 10.4 and v = 12

Solution:

In the given 2 sides of a triangle are 60°, 60°.

Sum of all the angles of a triangle = 180°

60° + 60° + third angle = 180°

⇒ third angle = 180° – 60° – 60°

⇒ third angle = 60°

All angles are equal, therefore the given triangle is an equilateral triangle.

⇒ All sides are equal in length.

⇒ v = 12

The line drawn from the top angle divides the triangle into two equal parts

and the line is perpendicular.

12 ÷ 2 = 6

Using Pythagoras theorem,

\text{Base}^2+\text{Opposite}^2=\text{Hypotenuse}^2

⇒ 6^2+\text{opposite}^2=12^2

⇒ 36+\text{opposite}^2=144

⇒ \text{opposite}^2=108

⇒ \text{opposite}=6\sqrt3=10.4

⇒ u = 10.4

Hence, u = 10.4 and v = 12.

7 0
3 years ago
Quesuon Z: 2 PES
cricket20 [7]

Answer:

124 ft2

Step-by-step explanation:

The yard is a 12ft square so the length and width would both be 12ft. You multiply the length and width of the yard to get the area of the yard so 12x12=144. You have the length and width of the flower bed so 5x4=20. Once you have the area of both you can subtract the area the flower bed takes up of the lawn. 144-20=124 ft2.

5 0
3 years ago
The answer is 5,-2,-3 but i need help with steps that make sense
olga nikolaevna [1]

\left\{\begin{array}{ccc}x+3y-z=2\\4x+2y+5z=1\\3x+z=12&\to z=12-3x\end{array}\right\\\\\text{substitute the value of z to the first and second equation}\\\\\left\{\begin{array}{ccc}x+3y-(12-3x)=2\\4x+2y+5(12-3x)=1\end{array}\right\\\\\left\{\begin{array}{ccc}x+3y-12+3x=2&|+12\\4x+2y+60-15x=1&|-60\end{array}\right\\\\\left\{\begin{array}{ccc}4x+3y=14&|\cdot2\\-11x+2y=-59&|\cdot(-3)\end{array}\right

\underline{+\left\{\begin{array}{ccc}8x+6y=28\\33x-6y=177\end{array}\right}\ \ \ \ |\text{add both sides of the equations}\\.\ \ \ \ \ \ \ 41x=205\ \ \ \ |:41\\.\ \ \ \ \ \ \ x=5\\\\\text{substitute the value of x to the first equation}\\\\4(5)+3y=14\\20+3y=14\ \ \ \ |-20\\3y=-6\ \ \ \ \ |:3\\y=-2\\\\\text{substitute the value of x to the equation:}\ z=12-3x\\\\z=12-3(5)=12-15=-3\\\\x=5,\ y=-2,\ z=-3\to(5,\ -2,\ -3)

6 0
3 years ago
How do I solve these?​
monitta

Answer:

I don't know

Step-by-step explanation:

is there a picture of a graph or anything

5 0
3 years ago
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