Answer:
There is a total of 60 mL of products produced
Explanation:
<u>Step 1:</u> Data given
8 mL of Cl2 gas with 22 mL of CH4
Pressure and temperature are kept constant
<u>Step 2:</u> The balanced equation
Cl2 (g) + CH4 (g) →HCl (g) + CH3Cl (g)
<u>Step 3:</u> Calculate the volume of the products
The ideal gas law is PV = nRT
Since the pressure and temperature are kept constant, and R is a constant.
V is directly proportional to n
the ratio of moles in an equation is proportional to the number of liters of gases
1 mol of Cl2 (g) + 1 mole of CH4 (g) ----------- 1 mole of HCl (g) + 1 mole of CH3Cl (g)
since n is directly proportional to V
1 litre of Cl2 (g) + 1 litre of CH4 (g) ----------- 1 litre of HCl (g) + 1 litre of CH3Cl (g)
V1n1 = V2n2
⇒ with V1 = the volume of the reactants = 22 + 38 = 60 mL
⇒ with n1 = the number of moles of reactants = 1+1 = 2 moles
⇒ with V2 = the volume of products = TO BE DETERMINED
⇒ with n2 = the number of moles of products = 1+1 = 2
60 mL * 2 = V2 * 2
V2 = 60 mL
This means :
38 mL + 22 mL produces a total of 60 mL of products
