Answer:
Explanation:
We have to make 100 mL 0f .405M HCl from 3 M solution of HCl .
volume of 3M to be taken required . Let this volume be V litre .
V litre of 3M will contain 3 V moles of HCl .
moles contained by 100 mL of ,405 HCl = .405 x .1 = .0405 moles .
So 3V = .0405
V = .0405 / 3 litre
= .0405 x 1000 / 4 mL
= 10.125 mL
So we have to take 10.125 mL of 3M HCl and add water to them to make its volume 100 mL .
PV=nRT will give you the answer I think. I haven’t worked with a certain unit in that problem
D: The atomic mass number
Answer:
The new volume will be 42, 7 L.
Explanation:
We use the gas formula, which results from the combination of the Boyle, Charles and Gay-Lussac laws. According to which at a constant mass, temperature, pressure and volume vary, keeping constant PV / T. The conditions STP are: 1 atm of pressure and 273 K of temperature.
P1xV1/T1 =P2xV2/T2
1 atmx 22,4 L/273K = 0,5atmx V2/260K
V2=((1 atmx 22,4 L/273K )x 260K)/0,5 atm= 42, 67L
That is correct c
Explanation
