A 1. 00 ml sample of an unknown gas effuses in 11. 1 min. an equal volume of h2 in the same apparatus under the same conditions effuses in 2. 42 minutes then the molar mass of the unknown gas is 41.9.
Molar mass of H2 = 2
Molar mass of unknown gas = ?
rate 1 = 11.1
rate 2 = 2.42
<h3>What is graham law? </h3>
Graham's law states that the rate of diffusion or effusion of a given gas is inversely proportional to the square root of its molar mass.
By apply graham law
Rate1/rate2 = sqrt(MW2/MW1)
![[\frac{rate1}{rate2} ]^{2} = \frac{MW2}{2} \\\\\\mw= 2[\frac{11.1}{2.42} ]^{2} \\\\= 20.97 X 2 \\\\= 41.9](https://tex.z-dn.net/?f=%5B%5Cfrac%7Brate1%7D%7Brate2%7D%20%5D%5E%7B2%7D%20%3D%20%5Cfrac%7BMW2%7D%7B2%7D%20%5C%5C%5C%5C%5C%5Cmw%3D%202%5B%5Cfrac%7B11.1%7D%7B2.42%7D%20%5D%5E%7B2%7D%20%5C%5C%5C%5C%3D%2020.97%20X%202%20%5C%5C%5C%5C%3D%2041.9)
Thus, we found that the molar mass of the unknown gas is 41.9.
Learn more about graham's law: brainly.com/question/12415336
#SPJ4
<h2>♨ANSWER♥</h2>
The respiratory system supplies oxygen to the blood and removes carbon dioxide. The brain monitors respiratory volume and blood gas levels. The brain regulates respiratory rate.
<u>☆</u><u>.</u><u>.</u><u>.</u><u>hope this helps</u><u>.</u><u>.</u><u>.</u><u>☆</u>
_♡_<em>mashi</em>_♡_
The names of the alkanes are 2,2- dimethylbutane, 2,4- dimethylhexane, 2,2,3,3- tetramethylbutane and 4- ethyl, 3,6- dimethyl heptane.
Alkanes are saturated hydrocarbon in the organic chemistry. These are organic compounds that consists of single bonded carbon and hydrogen atoms. The common formula for writing an alkane is given by CₙH₂ₙ₊₂.
Alkanes are further divided into three more types which are:
1. Chain alkanes
2. Cycloalkanes
3. Branched alkanes
Hydrogenation method is used for preparation of alkanes from alkene and alkyne.
The names of the given compounds are:
Part A:
2,2- dimethyl butane
Part B:
2,4- dimethyl hexane
Part C:
2,2,3,3- tetramethyl butane
Part D:
4- ethyl, 3,6- dimethyl heptane
Learn more about alkanes from the link given below.
brainly.com/question/16837399
#SPJ1
His distance and displacement are the same, which was 400 m
<h3>Further explanation</h3>
Given
Distance = 400 m
time = 2 min
Required
Distance and displacement
Solution
Distance is a scalar quantity that indicates the length of the trajectory that is traveled by an object within a certain interval. Distance has no direction, only has magnitude
Can be simplified distance = totals traveled
Displacement is a vector quantity that shows changes in the position of objects in a certain interval of time. Displacement has magnitude and direction
Can be simplified displacement = distanced traveled from starting point to ending point
From the definition above shows that the displacement and the distance that he traveled have the same value (magnitude), which is equal to 400 m
The value of the two will be different if he starts and finishes at the same point, then the displacement value is zero while the distance he has traveled is still 0
Answer:
The correct answer is option E.
Explanation:
Structures for the reactants and products are given in an aimage ;
Number of double bonds in oxygen gas molecule = 1
Number of double bonds in nitro dioxide gas molecule = 1
Number of single bond in in nitro dioxide gas molecule = 1
Number of triple bonds in nitrogen gas molecule = 1
![\Delta H=[2 mol\times \Delta H_{f,NO_2}]-[1 mol\times \Delta H_{f,N_2}-2 mol\times \Delta H_{f,O_2}]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5B2%20mol%5Ctimes%20%5CDelta%20H_%7Bf%2CNO_2%7D%5D-%5B1%20mol%5Ctimes%20%5CDelta%20H_%7Bf%2CN_2%7D-2%20mol%5Ctimes%20%5CDelta%20H_%7Bf%2CO_2%7D%5D)
(pure element)
(pure element )
The enthalpy of the given reaction is 15.86 kcal.
