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vladimir2022 [97]
3 years ago
5

What causes hydrogen bonds to rupture in ice

Chemistry
2 answers:
finlep [7]3 years ago
7 0
As water is boiled, kinetic energy causes<span> the </span>hydrogen bonds to break<span> completely and allows water molecules to escape into the air as gas (steam or water vapor). When water freezes, water molecules form a crystalline structure maintained by </span>hydrogen bonding<span>. Solid water, or </span>ice<span>, is less dense than liquid water.</span>
inn [45]3 years ago
7 0
Kinetic energy would cause the hydrogen bonds to rupture in ice!
I hope that helps and you do well! (:
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A pure substance has a sharp melting point (melts at one temperature) and a sharp boiling point (boils at one temperature). A mixture melts over a range of temperatures and boils over a range of temperatures. Homogeneous mixtures are called solutions.

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What describes the basis of the band theory of metallic bonding
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3 years ago
Convert to grams<br> 0.100 moles of Co2
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3 years ago
Complete combustion of a 0.350 g sample of a compound in a bomb calorimeter releases 14.0 kJ of heat. The bomb calorimeter has a
dexar [7]

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Its final temperature is 25.8 °C

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

There is a direct proportional relationship between heat and temperature. The constant of proportionality depends on the substance that constitutes the body as on its mass, and is the product of the specific heat by the mass of the body. So, the equation that allows calculating heat exchanges is:

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where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation (ΔT=Tfinal-Tinitial)

When a body transmits heat there is another that receives it. This is the principle of the calorimeter. Then the heat released by the compound will be equal to the heat obtained by the calorimeter.

In this case, you know:

  • Q= 14 kJ= 14,000 J
  • c= 3.55  \frac{J}{g*C}
  • m=1.20 kg= 1200 g (1 kg=1000 g)
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Replacing:

14,000 J= 3.55 \frac{J}{g*C}*1200 g*(Tfinal-22.5C)

Solving:

\frac{14,000J}{3.55\frac{J}{g*C} *1200 g} =T final - 22.5C

3.3=Tfinal - 22.5 C

3.3 + 22.5=Tfinal

Tfinal= 25.8 °C

<u><em>Its final temperature is 25.8 °C</em></u>

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3 years ago
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C number of particles dissolved
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