Answer:
b. laminar flow
the reynold number is 1329.26
Explanation:
Re = (V x D x ρ)/ η
where,
V = mean velocity = 15.9 cm/s = 0.159m/s
D = vessel diameter = 2.15cm = 0.0215m
ρ = blood density = 1050 kg/m3 = 0.00105 kg/cm3
η = dynamic viscousity= 2.70 × 10-3 Pa·s = 2.70 × 10-3 kg/m-s
applying the formular to calculate for reynolds number, Re =
Re = (V x D x ρ)/ η
=(0.159 x 0.0215 x 1050) / 2.70 × 10-3
=3.589/0.0027 = 1329.26
the Reynolds number for the blood leaving the heart through the aorta if the diameter of the aorta is 2.15 cm and the blood has a dynamic viscosity of 2.70 × 10-3 Pa·s, a density of 1050 kg/m3, and travels at a mean fluid velocity of 15.9 cm/s is 1329.26
which flow through the aorta in a Laminar flow
Note that
a) turbulen= Re >4000
b) laminar= Re <2300
c) transitioning between laminar and turbulen= Re between 2100 and 4000
Answer:
With few exceptions, all cells in a person’s body have the same DNA and genes. As cells divide and grow different genes are expressed, resulting in different cell types. As cells divide and grow different genes are expressed, resulting in different cell types.
Explanation:
Answer:
Yes, this population lies in Hardy-Weinberg equilibrium as it follows both the principles of Hardy-Weinberg.
Explanation:
Here ,
As per the first principle of hardy Weinberg, the sum of all the alleles at the locus must be equal to 1.
Thus,
Also, as per the second equation of Hardy Weinberg's equation-
Hence, this population lies in Hardy-Weinberg equilibrium as it follows both the principles of Hardy-Weinberg
The arrangement favor the rotational movement around the vertical axis. Although it is possible to have some flexion, extension and lateral bending moments also.
A.) Organic fossils. I hope that's right
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