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Pepsi [2]
3 years ago
11

2. solve 4w − 7k = 28 for k. show your work

Mathematics
1 answer:
NISA [10]3 years ago
5 0
4w-7k=28
-7k+4w+-4w=28+-4w
-7k=-4w+28
-7k/-7=-4w+28/-7
k=4/7w-4

:)
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3<br><img src="https://tex.z-dn.net/?f=%203%5Cfrac%7B4%7D%7B5%7D%20%20%5Cdiv%20%203%5Cfrac%7B1%7D%7B6%7D%20" id="TexFormula1" ti
Jobisdone [24]
Hey There!

Here is your answer:

First write the equation down:

-3 4/5 ÷ -3 1/6

Then put the mixed fractions into whole numbers:

-3 4/5= 5×-3=-15+4=-11= -11/5
&
-3 1/6= 6×-3=-18+1=-17= -17/6

Now right the new problem:

-11/5×6/-17

Now multiply:

-11×6=-66
5×-17=-85

Which means -66/-85 is your answer!

Hope this helps!
3 0
3 years ago
I NEED HELP PLS.......
Gekata [30.6K]
-4x - 2.4

explanation: 1.3 - 3.7 = -2.4
then you leave the -4x by itself since it’s the only variable
8 0
3 years ago
Read 2 more answers
Please help me first answer gets brainliest please dont play around
Crazy boy [7]

Answer:

8b- 13 6/7

Step-by-step explanation:

A product of 8 and b just means 8 x b or 8b.

13 6/7 less than that product means subtraction.

Therefore, it would be 8b - 13\frac{6}{7}

6 0
3 years ago
Read 2 more answers
Suppose that a, b \in \mathbb{Z}a,b∈Z, not both 00, and let d=\gcd(a, b)d=gcd(a,b). Bezout's theorem states that dd can be writt
lara [203]

Answer:

Step-by-step explanation:

Recall that we say that d | a if there exists an integer k for which a = dk. So, let d = gcd(a,b) and let x, y be integers. Let t = ax+by.

We know that d | a, d | b so there exists integers k,m such that a = kd and b = md. Then,

t = ax+by = (kd)x+(md)y = d(kx+my). Recall that since k,  x, m, y are integers, then (kx+my) is also an integer. This proves that d | t.

3 0
3 years ago
3(2x) + 3(-1) = -21 <br><br>6x - 3 = -21<br> What property is being used ?
kaheart [24]
Distributive property, since 3(2x) you distribute and get 6x
4 0
3 years ago
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