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kifflom [539]
3 years ago
6

Can someone please help me on this question

Mathematics
1 answer:
zalisa [80]3 years ago
8 0

Answer:

124 students

Step-by-step explanation:

let number of boys be 11x and girls be 9x.

A.T.Q 124 more boys than girls

equation=

11x = 9x + 124

11x- 9x = 124

2x = 124

x = 124/2 = 62

boys= 62 * 11 = 682

girls= 62 * 9 = 558

total = 558+682 = 1240 students

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3 years ago
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At Dave's diner, 2 sandwiches and 2 drinks cost $12. You can buy 5 drinks for the cost of one sandwich.
hram777 [196]
If you’re asking for the cost of the drink, the drink would be $1. This is because 2 sandwiches would cost $10 and that means 1 sandwich would make it $5. If 2 sandwiches cost $10, the remaining $2 in the $12 dollars would be the drinks. 2 drinks for $2 would make 1 drink for $1. So the cost of 5 drinks is $5 or $1 per drink.

If confused, don’t be shy to ask :)
8 0
3 years ago
businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message
KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

             =1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0
3 years ago
Help please will mark u brainliest !!!!!
kari74 [83]

Step-by-step explanation: To make a line paralle to another, the slope has to be the same such as the "m" in "y=mx+b" the y-intercept or "b" could be different. In this case, the slope is -7. So the question mark should be -7.

4 0
4 years ago
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20. The total mass of three boxes, A, B, and C, is 1.95 kg. The mass of Box A is 700 g. The mass of Box B is 4 times the mass of
Ksju [112]

Answer:

<h3>Mass of B in Kg = -558.44kg</h3>

Step-by-step explanation:

LET'S DO THIS!

Total mass of A, B and C = 1.95kg

Mass of A = 700 kg

Mass of B = 4x the mass of c (4 x C) which is 4c

Mass of C = ? ( let's call it C )

<h3>Adding all together </h3>

700 + 4c + C = 1.95

<h3>Add like terms</h3>

700 + 5C = 1.95

5C = 1.95 - 700

5C = -698.05

C = -698.05 ÷ 5

<h3>C = -139.61</h3>

<h3>To find B now </h3><h3>Remember they said B is 4 times the mass of C and C = -139.61</h3>

therefore B = 4 × -139.61

<h3>B = -558.44 kg </h3>

<h3>To check if we are correct, we add the masses of A, B and C to see if it equals their total mass which is 1.95kg</h3>

<h3>Using your calculator: </h3>

= 700 + ( -558.44 ) + ( -139.61 )

= 700 - 558.44 -139.61

= 1.95 kg

Which makes us CORRECT ✅.

<h3>Hope this helps.</h3><h3>Good luck ✅.</h3>

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