Explanation:
According to p²+q²+2pq=1 (Hardy-Weinberg equilibrium)
heterozygote allele will be always 2pq
<u>1. Population</u>
1. A blood group has two genotypes- IAIA and IAIO
The genotype frequency will be-
IAIA= 0.3 X 0.3 = 0.9
IAIO= (0.3 x 0.6) x 2= 0.36
Total genotype frequency = 0.9+ 0.36 =0.45 or 45%
Now 45% of 540,000= 2,43000 (A blood group)
2. B blood group has two genotypes- IAIB and IBIO
The genotype frequency will be-
IBIB= 0.1 x 0.1 = 0.1
IBIO= (0.1 x 0.6)-=0.12
Total genotype frequncy= 0.13 or 13%
popluation with B blood group= 13% of 540,000 will be 70,200
3. AB blood group is IAIB
2 x IAIB= (0.3 x 0.1) x 2= 0.6
popluation with B blood group= 6% of 540,000= 32,400
4. O blood group
2. Heterozygote
IBIO blood group
= (0.1 x 0.6) x 2
= 0.12 or 12%
= 12%
