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3 years ago

Sugar crosses the cell membrane from an area of high concentration to an area of low concentration using

Biology

1 answer:

umka21 [38]3 years ago

5 0

Facilitated diffusion

i also included a photo of the explanation of facilitated diffusion. i hope this is helpful

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Antibodies are composed of two types of peptides, heavy chains and light chains. One of the major classes of antibody molecules

timurjin [86]

Answer and Explanation:

a. form the antigen-binding site ⇒ both chains

The antigen-binding site is formed by one hypervariable region of the light chain (VL) and one hypervariable region of the heavy chain (VH). So, both type of chains contributes to antigen recognition.

b. contain multiple variable domains ⇒ none

Both chains - light and heavy - contain <u>only one</u> variable domain (VL and VH).

c. are found in the Fab fragment ⇒ both chains

The Fab fragment is composed of portions of both light and heavy chains: each portion contains one variable domain and one constant domain. The Fab fragment binds specifically the antigen.

d. are found in the FC fragment ⇒ heavy chains

The Fc region is composed of portions of heavy chains (CH² and CH³), so it contains constant domains.

e. contain only one constant domain ⇒ light chains

Each light chain contains one variable domain (VL) and one constant domain (CL).

f. contain multiple constant domains ⇒ heavy chains

Each heavy chain contains three constant domains: CH¹, CH² and CH³.

g. contain only one variable domain ⇒ both chains

Both light and heavy chains contain one variable domain. The difference is given by the number of constant domains: light chains have 1 constant domain while heavy chains have 3 constant domains.

8 0

3 years ago

Why is evolution considered a theory and not a law

cluponka [151]

Theories explain phenomena, whilst laws are generalizations which characterize them.

3 0

2 years ago

How much 3M NaOH (MW=40) can be made from 10.0mL of a 10M solution?

vaieri [72.5K]

Explanation:

The given data is as follows.

$M_{1}$ = 3 M, $V_{1}$ = ?

$M_{2}$ = 10 M, $V_{2}$ = 10.0 ml

Therefore, calculate the volume of given solution as follows.

$M_{1} \times V_{1}$ = $M_{2} \times V_{2}$

Now, putting the given values into the above formula as follows.

$M_{1} \times V_{1}$ = $M_{2} \times V_{2}$

$3 M \times V_{1}$ = $10 M \times 10.0 ml$

$V_{1}$ = 33.3 ml

or, = 0.033 L (as 1 ml = 0.001 L)

Since, molarity of NaOH is given as 3 M and its volume is calculated as 33.3 ml.

Molarity = $\frac{\text{mass of solute}}{\text{molar mass of solute}} \times \frac{1}{\text{volume in L}}$

3 M = $\frac{mass}{40 g/mol \times 0.033 L}$

mass = 3.96 g

Therefore, we can conclude that mass of NaOH is 3.96 g.

8 0

3 years ago

Define atomic number, atomic weight and atomic mass.

lozanna [386]

Atomic number shows the number of protons in the nucleus of an atom.
Atomic weight shows the is an another term for atomic mass, which means <span>It is approximately equivalent to the number of protons and neutrons in the atom (the mass number) or to the average number allowing for the relative abundances of different isotopes.</span>

6 0

3 years ago

The primary stimulus for release of adrenal medullary hormones comes from Select one: a. the kidneys. b. aldosterone. c. the ant

Natasha_Volkova [10]

Answer:

Correct answer is ''e'' the sympatetic nervows system

Explanation:

THE ENDOCRINE SYSTEM How does the endocrine orchestra work? 1- Nervous Stimuli to the Hypothalamus  production of releasing (stimulatory) or inhibitory hormones, transported via a portal system of vessels to the anterior pituitary gland 2- Anterior Pituitary Gland  pituitary trophic hormones 3- Pituitary trophic hormones stimulate Peripheral Endocrine Glands  production of peripheral hormones 4- Hormone/Receptor Interactions in target organs  hormone actions 5- Peripheral hormones exert Negative Feedback Mechanisms  supression of hypothalamic & pituitary hormones.

6 0

3 years ago

Read 2 more answers