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Juliette [100K]
3 years ago
10

In the case of the bombina frogs given in your text, there was evidence of hybridization because

Biology
2 answers:
IgorC [24]3 years ago
5 0

In the case of the Bombina frogs, the evidence that hybrid zone stability is occurring was the consistent pattern from annual to annual of declining frequency of yellow-bellied toad alleles with distance from the edge of their range. This is a clear evidence that hybridization is taking place yearly in the Bombina frogs.

Whitepunk [10]3 years ago
3 0

Answer:

On account of the Bombina frogs, the proof that half and half zone.  

Explanation:

strength is happening was the steady example from yearly to yearly of declining  recurrence of yellow-bellied frog alleles with separation from the edge of their  extend. This is an unmistakable proof that hybridization is occurring yearly in  the Bombina frogs.orbital hybridisation is the idea of blending nuclear orbitals into new half and half orbitals appropriate for the matching of electrons to shape synthetic bonds in valence bond hypothesis.

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A certain buffer is made by mixing a weak acid HA and its conjugate base A–. When HA is present at a concentration of 0.5 mM and
MAVERICK [17]

Answer:The ratio of the concentrations of HA  and A^- when the buffer has a pH of 7.02 is 0.69

Explanation:

The dissociation constant for formic acid = K_a=1.8\times 10^{-4}

Concentration of HA= 0.5 mM

Concentration of A^-= 0.1 mM

pH = 6.16

First we have to calculate the value of K_a.

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[A^-}{[HA]}

Now put all the given values in this expression, we get:

6.16=pK_a+\log (\frac{[0.1]}{0.5})

pK_a=6.86

To calculate the ratio of the concentrations of HA  and A^- when the buffer has a pH of 7.02.

Using Henderson Hesselbach equation :

7.02=6.86+\log \frac{[A^-]}{[HA]}

7.02=6.86+\log \frac{[A^-]}{[HA]}

\frac{[A^-]}{[HA]}=1.44

\frac{[HA]}{[A^-]}=0.69

Thus the ratio of the concentrations of HA  and A^- when the buffer has a pH of 7.02 is 0.69

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3 years ago
1. After mitosis in animals, cytokinesis takes place. What happens during cytokinesis?
il63 [147K]
The correct answers are as follows:
1. During cytokinesis, THE CELL MEMBRANE PINCHES IN TO FORM TWO NEW CELLS.
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2. The correct order of the phases of mitosis are as follows: PROPHASE, METAPHASE, ANAPHASE AND TELOPHASE.
Mitosis is the process of cell division by which a cell is divided into two new cells. The process occurs in four basic stages and result in the formation of two new cells.
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Amplexus refers to the mating positions of frogs and toads during sexual reproduction. Mating system refers to the number of mating partners that an animal has during the mating period. Gamete formation is the process by which sex cells are made and it occurs in both male and female animals.
4. As a cell is preparing to divide by mitosis, the DNA MUST BE COPIED.
When a cell is getting ready to divide by mitosis, it will undergo a stage called interphase, during which the cell prepare for cell division. During interphase, the cell undergo some process and these include the copying of the DNA. The cell copies its DNA so that it has two copies of each strand.
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