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lorasvet [3.4K]
3 years ago
15

What is the equation of the line ?

Mathematics
1 answer:
Ronch [10]3 years ago
7 0

Look at the picture.

The point-slope form:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (-3, -3) and (2, 0). Substitute:

m=\dfrac{0-(-3)}{2-(-3)}=\dfrac{3}{5}\\\\y-0=\dfrac{3}{5}(x-2)\qquad|\text{use distributive property}\\\\y=\dfrac{3}{5}x-\dfrac{6}{5}\qquad|\cdot5\\\\5y=3x-6\qquad|-5y\\\\0=3x-5y-6\qquad|+6\\\\3x-5y=6

Answer:

point-slope form: y=\dfrac{3}{5}(x-2)

slope-intercept form: y=\dfrac{3}{5}x-\dfrac{6}{5}

standard form: 3x-5y=6

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