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andrew11 [14]
3 years ago
13

Which data set represents the box plot? A) {56, 66, 93, 90, 57, 66, 69, 68, 76, 64, 48} B) {56, 66, 95, 90, 57, 66, 69, 68, 76,

64, 51} C) {56, 66, 95, 90, 57, 71, 71, 68, 76, 64, 51} D) {56, 66, 98, 90, 57, 66, 69, 68, 76, 64, 51}
Mathematics
2 answers:
jeka943 years ago
8 0

answer  

b

the answer is because I just took the test on usatest prep

iVinArrow [24]3 years ago
4 0

Answer:

B) {56, 66, 95, 90, 57, 66, 69, 68, 76, 64, 51}

Step-by-step explanation:

{56, 66, 95, 90, 57, 66, 69, 68, 76, 64, 51} is the only data set that matches the maximum and minimum, upper and lower quartile, and median values.

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A scientist invents a car that can travel for many hours without stopping for fuel. The car travels around a track at 54 miles a
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Step-by-step explanation:

Hi, to answer this question we have to apply the next formula:  

Distance = Speed rate x time

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3 0
3 years ago
One sample has a mean of M= 6, and a second sample has a mean of M = 12. The two samples are combined into a single set of score
lakkis [162]

Answer:

a) 9

b) 10

c) 8

Step-by-step explanation:

We are given the following in he question:

Mean of sample A = 6

Mean of sample B = 12

Formula:

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

\dfrac{\displaystyle\sum x_a}{n_a} = 6\\\\\dfrac{\displaystyle\sum x_b}{n_b} = 12

a) original samples have n = 4 scores

\dfrac{\displaystyle\sum x_a}{4} = 6,\sum x_a = 24\\\\\dfrac{\displaystyle\sum x_b}{4} = 12,\sum x_b = 48\\\\\text{Combined mean} = \displaystyle\frac{\sum x_a + \sum x_b}{4+4}=\frac{24 + 48}{4 + 4} = 9

b) first sample has n = 3 and the second sample has n = 6

\dfrac{\displaystyle\sum x_a}{3} = 6,\sum x_a = 18\\\\\dfrac{\displaystyle\sum x_b}{6} = 12,\sum x_b = 72\\\\\text{Combined mean} = \displaystyle\frac{\sum x_a + \sum x_b}{3+6}=\frac{18+72}{3+6} = 10

c) first sample has n = 6 and the second sample has n = 3

\dfrac{\displaystyle\sum x_a}{6} = 6,\sum x_a = 36\\\\\dfrac{\displaystyle\sum x_b}{3} = 12,\sum x_b = 36\\\\\text{Combined mean} = \displaystyle\frac{\sum x_a + \sum x_b}{6+3}=\frac{36+36}{6+3} = 8

7 0
3 years ago
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