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marin [14]
3 years ago
9

5x+3y=28 3x+y=12 please solve algebraically

Mathematics
1 answer:
Aleks04 [339]3 years ago
8 0
The answer is x= 2, y = 6

Solve for y in the second equation, so you have y= -3x + 12. Now plug that in for y in the first equation: 5x + 3( -3x +12) = 28.
Now simplify: 5x + -9x + 36 = 28: -4x = -8; so x = 2.
Now plug x=2 into either equation to solve for y:
3(2) + y = 12; 6 + y = 12; so y = 6
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Change the messy words into numerals
3     times          a number         minus            2           equals         13
3          ×                n                     -                 2               =               13

3n - 2 = 13
take 2 to the other side
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Divide by 3 on either sides to isolate n
\frac{3n}{3} = \frac{15}{3}
3 and 3 cancels out

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check:
3 times 5 minus 2 equals 13
3     ×    5       -      2     =     13
15    -      2        =          13
13            =               13

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