3 years ago

5x+3y=28 3x+y=12 please solve algebraically

1 answer:

8 0

The answer is x= 2, y = 6

Solve for y in the second equation, so you have y= -3x + 12. Now plug that in for y in the first equation: 5x + 3( -3x +12) = 28.
Now simplify: 5x + -9x + 36 = 28: -4x = -8; so x = 2.
Now plug x=2 into either equation to solve for y:
3(2) + y = 12; 6 + y = 12; so y = 6

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