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ikadub [295]
3 years ago
13

There is 3/4 of a box of cereal remaining. You eat 2/5 of the remaining cereal. What fraction of the box do you eat?

Mathematics
1 answer:
Bumek [7]3 years ago
6 0
5/8 of the box is right
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kap26 [50]
It’s either A or C I would pick A even though they don’t really make sense.
5 0
3 years ago
The equation of line a is y=3/4x-3 If line b runs parallel to line a and passes
katen-ka-za [31]

Answer:

y = -4/3 x - 1/3

Step-by-step explanation:

y = -4/3 x + b

5 = -4/3 (-4) + b

15 = 16 + 3b

b = -1/3

y = -4/3 x - 1/3

5 0
3 years ago
"How much do students pay, on average, for textbooks during the first semester in college? From a random sample of 400 students
dezoksy [38]

Answer: The margin of error = 3.71, confidence interval = (354.04, 361.46) and it means that mean cost is lies within the confidence interval.

Step-by-step explanation:

Since we have given that

Sample size = 400

Mean = $357.75

Standard deviation = $37.89

At 95% confidence level, z = 1.96

We first find the margin of error.

Margin of error is given by

z\times \dfrac{\sigma}{\sqrt{n}}\\\\=1.96\times \dfrac{37.89}{\sqrt{400}}\\\\=3.71

95% confidence interval would be

\bar{x}\pm \text{margin of error}\\\\=357.75\pm 3.71\\\\=(357.75-3.71,357.75+3.71)\\\\=(354.04,361.46)

Hence, the margin of error = 3.71, confidence interval = (354.04, 361.46) and it means that mean cost is lies within the confidence interval.

7 0
3 years ago
If a baseball team's ratio of wins to losses is 5 to 4, what is the ratio of wins to total games played?
lara [203]
I believe it's 5 to 9 since out of 9 games they win 5 and lose 4. This doesn't account for draws or anything, though.
8 0
3 years ago
Suppose the true proportion of voters in the county who support a restaurant tax is 0.54. Consider the sampling distribution for
Eva8 [605]

Answer:

The correct answer is:

(a) 0.54

(b) 0.0385

Step-by-step explanation:

Given:

Restaurant tax,

p = 0.54

Sample size,

n = 168

Now,

(a)

The mean will be:

⇒ μ \hat{p}= p

         =0.54

(b)

The standard error will be:

\sigma \hat{p} = \sqrt{[\frac{p(1-p)}{n} ]}

    = \sqrt{[\frac{(0.54\times 0.46)}{168} ]}

    = \sqrt{[\frac{(0.2484)}{168} ]}

    = 0.0385

6 0
2 years ago
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