Answer:
it growth
negative infinity to positive
-7, positive infinity
y inter = -6
horizontal asym = -7
Step-by-step explanation:
Answer:
d = 5,35 ft
Step-by-step explanation: See annex
Figure in annex is clear,
sin ∠42⁰ = d / 8
And
sin ∠42⁰ = 0.669
d/8 = 0,669
d = 0,669*8
d = 5,35 ft
5782/24=240 since we round down to s whole.
Multiply again by 24.
240*24=5760
There are 5782-5760=22 priority seats.
The correct answer is 22.
Answer:
75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.
Step-by-step explanation:
The question is missing. It is as follows:
Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69 104 125 129 60 64
Assume that the population of x values has an approximately normal distribution.
Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)
75% Confidence Interval can be calculated using M±ME where
- M is the sample mean weight of the wild mountain lions (
)
- ME is the margin of error of the mean
And margin of error (ME) of the mean can be calculated using the formula
ME=
where
- t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)
- s is the standard deviation of the sample(31.4)
Thus, ME=
≈16.66
Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5