Answer:
D. HL (hypotenuse leg)
Step-by-step explanation:
There are two triangles in the picture, ABQ and CDP. The condition for the hypotenuse leg are:
1. both triangles are right triangle
2. the hypotenuse and one of the leg/side is equal
Both B and D angle is 90 degrees, so both triangles is right triangle. The hypotenuse for the triangle is AQ and PC, and both are equal. One of the triangles legs also equal, which is AB and CD. With that, you fulfill HL postulate for the congruent triangle.
Don't confuse this with SAS theorem for the same angle should be on the middle of two equal sides.
1st one would be x/9
2nd one is -3-x/2
<span>A) 2x -5y +z = 1
B) 3 y + 2z = 5
C) -24 z = 48
Those 3 equations you typed were somewhat squished together.
Did I retype those correctly?
Let me know and I'll solve it.
</span>
Answer:
Step-by-step explanation:
