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irina1246 [14]
3 years ago
14

K + 1/3 = 5 1/8 . Please help

Mathematics
1 answer:
guapka [62]3 years ago
6 0

Answer:

4.7916

4 19/24

I hope this helped good luck! :)

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Without solving determine the number of real solutions for each quadratic equation
seropon [69]

Answer:

b^2-4b+3=0

b²-3x-b+3=0

b(b-3)-1(b-3)=0

(b-3)(b-1)=0

either

b=3 or b=1

.

2n^2 + 7 = -4n + 5

2n²+4n+7-5=0

2n²+4n+2=0

2(n²+2n+1)=0

(n+1)²=0/2

:.n=-1

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x - 3x^2 = 5+ 2x - x^2

0=5+ 2x - x^2-x +3x^2

0=5+x+2x²

2x²+x+5=0

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={-1±√-39}/2

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2 years ago
David earned a total of $378.75 in 15 hours. How much did David earn per hour? NO GUESSES NO LINKS NO BOTS
enot [183]

Answer: $25.25

Step-by-step explanation:

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3 0
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5 x a x 5 x a simplified
Fittoniya [83]

Answer:

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I know that real numbers consist of the natural or counting numbers, whole numbers, integers, rational numbers and irrational nu
ra1l [238]

The imaginary unit i belongs to the set of complex numbers, denoted by \mathbb C. These numbers take the form a+bi, where a,b are any real numbers.

The set of real numbers, \mathbb R, is a subset of \mathbb C, where each number in \mathbb R can be obtained by taking b=0 and letting a be any real number.

But any number in \mathbb C with non-zero imaginary part is not a real number. This includes i.

  • "is it possible that i can use an imaginary number for a real number"

I'm not sure what you mean by this part of your question. It is possible to represent any real number as a complex number, but not a purely imaginary one. All real numbers are complex, but not all complex numbers are real. For example, 2 is real and complex because 2=2+0i.

There are some operations that you can carry out on purely imaginary numbers to get a purely real number. A famous example is raising i to the i-th power. Since i=e^{i\pi/2}, we have

i^i=\left(e^{i\pi/2}\right)^i=e^{i^2\pi/2}=e^{-\pi/2}\approx0.2079

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3 years ago
Help please for big points​
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Answer:

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Step-by-step explanation:

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