3 years ago

Help me with 8 through 12 please and thank you only 4 questions

Mathematics

1 answer:

Vera_Pavlovna [14]3 years ago

5 0

Answer:

i can't do that I don't know how I'm sorry

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Fifteen equals s over thirteen

zimovet [89]

Can you restate the question please

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3 years ago

Find the length of the third side to the nearest tenth.<br> 3 7

kogti [31]

Answer:

uhm 5?

Step-by-step explanation:

because 3 we move 1 more is 4.

and 7 we go -1 which is 6 so we have 5 in the middle so the answer is 5!

5 0

3 years ago

9n+21−3n−24 simplify

Thepotemich [5.8K]

Alright First you combine the like terms.
9n - 3n = 6n
21 - 24 = -3

Rewrite the simplified equation
6n - 3 = 0

Solve for n
6n = 3
n = 3/6
n = 1/2

Ask if you need more help! :)

6 0

3 years ago

Name the subsets of the real numbers to which each number belongs. The square root of 11

Zolol [24]

Well the answer for the square root of 11

irrational number

and real number

4 0

3 years ago

Find the volume of the largest rectangular box in the first octant with three faces in the coordinate planes and one vertex in t

makkiz [27]

Answer:

Step-by-step explanation:

$x + 2y + 3z = 12$

$z=\frac{12-x-2y}{3}$

Volume = $V=f(x,y) = xy(\frac{12-x-2y}{3} )$

find partial derivatives using product rule

$f_x =\frac{y}{3} (12-2x-2y)\\f_y = \frac{x}{3} (12-x-4y)$

i.e.

Using maximum for partial derivatives, we equate first partial derivative to 0.

y=0 or x+y =6

x=0 or x+4y =12

Simplify to get y =2, x = 4

thus critical points are (4,2) (6,0) (0,3)

Of these D the II derivative test gives

D<0 only for (4,2)

Hence maximum volume is when x=4, y=2, z= 4/3

Max volume is = 4(2)(4/3) = 32/3

6 0

3 years ago