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boyakko [2]
2 years ago
7

Help me with 8 through 12 please and thank you only 4 questions

Mathematics
1 answer:
Vera_Pavlovna [14]2 years ago
5 0

Answer:

i can't do that I don't know how I'm sorry

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1. When John received his W2, he received several copies. Why was he sent multiple copies of this form?
Firlakuza [10]
<span>1. W2 is a form every empoyer send to his employees that reports the annual wagges of the employees and the amount of taxes. This W2 form is sent at the end of the year. The employees get at least two copies of this form. One copy is for the employee and the other is for IRS (Internal revenue Service) to report the wages. 2. John's employeer sent John the W-2 form. Every employer is obligated to deliver W2 form to all of his employees. John can get copy of the W-2 form for IRS (Internal Revenue Service). This is done for a fee. 3/ In order to know how much John did in wages in the 2014 we must have knowledge of John's salaty. Without this information we can not clculate the wages. </span>
7 0
3 years ago
Read 2 more answers
Given x= -2, mark and place these six expressions
zaharov [31]

Answer:

-4, x, |-1.5| , -x, |5|, |6|

Step-by-step explanation:

X = -2

-X = 2

|-1.5| = 1.5

|5| = 5

|6| = 6

4 0
2 years ago
Find the minimum and maximum of f(x,y,z)=x^2+y^2+z^2 subject to two constraints, x+2y+z=4 and x-y=8.
Alika [10]
The Lagrangian for this function and the given constraints is

L(x,y,z,\lambda_1,\lambda_2)=x^2+y^2+z^2+\lambda_1(x+2y+z-4)+\lambda_2(x-y-8)

which has partial derivatives (set equal to 0) satisfying

\begin{cases}L_x=2x+\lambda_1+\lambda_2=0\\L_y=2y+2\lambda_1-\lambda_2=0\\L_z=2z+\lambda_1=0\\L_{\lambda_1}=x+2y+z-4=0\\L_{\lambda_2}=x-y-8=0\end{cases}

This is a fairly standard linear system. Solving yields Lagrange multipliers of \lambda_1=-\dfrac{32}{11} and \lambda_2=-\dfrac{104}{11}, and at the same time we find only one critical point at (x,y,z)=\left(\dfrac{68}{11},-\dfrac{20}{11},\dfrac{16}{11}\right).

Check the Hessian for f(x,y,z), given by

\mathbf H(x,y,z)=\begin{bmatrix}f_{xx}&f_{xy}&f_{xz}\\f_{yx}&f_{yy}&f_{yz}\\f_{zx}&f_{zy}&f_{zz}\end{bmatrix}=\begin{bmatrix}=\begin{bmatrix}2&0&0\\0&2&0\\0&0&2\end{bmatrix}

\mathbf H is positive definite, since \mathbf v^\top\mathbf{Hv}>0 for any vector \mathbf v=\begin{bmatrix}x&y&z\end{bmatrix}^\top, which means f(x,y,z)=x^2+y^2+z^2 attains a minimum value of \dfrac{480}{11} at \left(\dfrac{68}{11},-\dfrac{20}{11},\dfrac{16}{11}\right). There is no maximum over the given constraints.
7 0
3 years ago
Whats 2 1/3 - 1 3/4 in simplest form
Aleonysh [2.5K]

Answer:

7/12

Step-by-step explanation:

5 0
2 years ago
What is the reciprocal of 3 2/3
deff fn [24]

Answer:

the answer is 5

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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