Answer:
0.077 M
Explanation:
Data Given :
The concentration of half normal (NaCl) saline = 0.45g / 100 g
So,
Volume of Solution = 100 g = 100 mL
Volume of Solution in Liter = 100 mL / 1000
Volume of Solution = 0.1 L
molar mass of NaCl = 58.44 g/mol
Molarity:
Molarity is the representation of the solution. It is amount of solute in moles per liter of solution and represented by M
Formula used for Molarity
M = moles of solute / Liter of solution . . . . . . . . . . (1)
Now to find number of moles of Nacl
no. of moles of NaCl = mass of NaCl / molar mass
no. of moles of NaCl = 0.45g / 58.44 g/mol
no. of moles of NaCl = 0.0077 g
Put values in the eq (1)
M = moles of solute / Liter of solution . . . . . . . . . . (1)
M = 0.0077 g / 0.1 L
M = 0.077 M
So the molarity of half-normal saline solution (0.45% NaCl) = 0.077 M
The answer is 600. A sample of C3H8O which contains two
hundred molecules, it also holds six hundred carbon atoms. A carbon atom holds
six electrons, four of its electrons are found in its valence shell or also
known as its outer shell.
Answer: The percent yield of lithium chloride if a reaction starts with 20.0 g lithium hydroxide and yields 6.00 g lithium chloride is 17.2 %
Explanation:
The balanced chemical reaction is
To calculate the moles, we use the equation:
a) moles of 
b) moles of 
According to stoichiometry :
1 mole of produces = 1 mole of
Thus 0.83 moles of produce=
of
Mass of 
The theoretical yield of = 34.9 g
The experimental yield of ethanol = 6.00 g
Now we have to calculate the percent yield of ethanol.
Therefore, the percent yield is, 17.2 %
A triple beam balance measures mass.
A weigh scale measures weight.
A hydrometer measures density
A thermometer measures temperature
