Answer:
the correct answer is A, Hg22+ on edge 2020
Explanation:
i took the review
<u>Given:</u>
Mass of Ag = 1.67 g
Mass of Cl = 2.21 g
Heat evolved = 1.96 kJ
<u>To determine:</u>
The enthalpy of formation of AgCl(s)
<u>Explanation:</u>
The reaction is:
2Ag(s) + Cl2(g) → 2AgCl(s)
Calculate the moles of Ag and Cl from the given masses
Atomic mass of Ag = 108 g/mol
# moles of Ag = 1.67/108 = 0.0155 moles
Atomic mass of Cl = 35 g/mol
# moles of Cl = 2.21/35 = 0.0631 moles
Since moles of Ag << moles of Cl, silver is the limiting reagent.
Based on reaction stoichiometry: # moles of AgCl formed = 0.0155 moles
Enthalpy of formation of AgCl = 1.96 kJ/0.0155 moles = 126.5 kJ/mol
Ans: Formation enthalpy = 126.5 kJ/mol
Answer:
The answer to your question is 0.036 M
Explanation:
Data
Molarity = ?
mass = 4.0 grams KOH
Volume = 2 L
Molecular mass KOH = 39 + 16 + 1 = 56 g
Formula
Process
1.- Calculate the moles of KOH using proportions
56 g of KOH ---------------- 1 mol
4 g of KOH ---------------- x
x = (4 x 1) / 56
x = 0.071 moles
2.- Substitute the values in the formula to find Molarity
3.- Simplification and result
Molarity = 0.036 M
Answer:the atoms of a solid aluminium can are close together vibrating in a rigid structure if the can is warmed up on a hot plate
Explanation:
Answer:
neither they both have the same molecule #
Explanation: