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Brrunno [24]
3 years ago
5

Which event would be impossible to explain by using John Dalton's model of the atom​

Chemistry
1 answer:
lisov135 [29]3 years ago
8 0

Answer:

we need the model to answer

Explanation:

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56. What would be the valence electrons of 14Si, 16S, 32Ge respectively?
Leokris [45]

Answer: D. 4,6,4

Explanation:

The valence electron is the electron found in the outermost shell of an atom, and participates in bond formation.

For the following element, the valence electron can be noticed when we write the electronic configuration of each element.

Silicon =  1s2 2s2 2P6 3s2 3p2

Sulphur = 1s2 2s2 2P6 3s2 3p4

Germanium =  1s2 2s2 2P6 3s2 3p6 3d10 4s2 4p2

8 0
2 years ago
A polypeptide in its native conformation has weak interactions between its R groups. However, when that same polypeptide is dena
sasho [114]

Answer:

A protein is more stable in its native form, because apart of weak interactions between R groups, it also presents other stronger interactions, as those including covalent bonds  

Explanation:

For example, covalent bonds between sulfur atoms when disulfide bridges are built.  These links are very difficult to break and maintains the protein shape.  Disulfide bonds are a few but they use to incide in the structure of native proteins

8 0
3 years ago
Chem please help theres a photo attatched
a_sh-v [17]

Answer:

the top one is 100.000 and bottom one is 100.000

Explanation:

8 0
2 years ago
Read 2 more answers
A form of energy that is stored in a stretched rubber band is called
storchak [24]
You input potential (stored<span>) </span>energy<span> into the </span>rubber band<span> system when you </span>stretched<span> the</span>rubber band<span> back. Because it is an </span>elastic<span> system, this kind of potential </span>energy<span> is specifically </span>called elastic<span> potential </span>energy<span>. ... When the </span>rubber band<span> is released, the potential </span>energy<span> is quickly converted to kinetic (motion) </span>energy<span>.</span>
6 0
2 years ago
Calculate the mass of magnesium carbonate ( MgCO3), in grams, required to produce 110.0 g of carbon dioxide using the following
bearhunter [10]

Answer:

210.7~g~MgCO_3

Explanation:

We have to start with the <u>reaction</u>:

MgCO_3~->~MgO~+~CO_2

We have the same amount of atoms on both sides, so, we can continue. The next step is to find the <u>number of moles</u> that we have in the 110.0 g of carbon dioxide, to this, we have to know the <u>atomic mass of each atom</u>:

C: 12 g/mol

O: 16 g/mol

Mg: 23.3 g/mol

If we take into account the number of atoms in the formula, we can calculate the <u>molar mass</u> of carbon dioxide:

(12*1)+(16*2)=44~g/mol

In other words: 1~mol~CO_2=~44~g~CO_2. With this in mind, we can calculate the moles:

110~g~CO_2\frac{1~mol~CO_2}{44~g~CO_2}=25~mol~CO_2

Now, the <u>molar ratio</u> between carbon dioxide and magnesium carbonate is 1:1, so:

2.5~mol~CO_2=2.5~mol~MgCO_3

With the molar mass of MgCO_3 ((23.3*1)+(12*1)+(16*3)=84.3~g/mol. With this in mind, we can calculate the <u>grams of magnesium carbonate</u>:

2.5~mol~MgCO_3\frac{84.3~g~MgCO_3}{1~mol~MgCO_3}=210.7~g~MgCO_3

I hope it helps!

8 0
3 years ago
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