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2 years ago

Dosage calculation order: 3 mg available: 2 mg per 6 ml how many ml will be given?

Chemistry

1 answer:

Anna35 [415]2 years ago

3 0

9ml will be given for the case of dosage calculation order: 3 mg available: 2 mg per 6 ml

Conversion factors are necessary for dosage calculation, such as when translating from pounds to kilograms or liters to milliliters. This approach, which is straightforward in design, enables physicians to deal with different units of measurement and convert factors to arrive at the solution.

dosage calculation techniques serve as a second or third check on the accuracy of the previous computation techniques. Dimensional Analysis, Ratio Proportion, and Formula or Desired Over Have Method are the three main approaches for dosage calculation. dosage calculations are frequently prescribed and labeled based on their weight or, for solutions, their strength, which is the amount of weight dissolved or suspended in a given volume.

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49. Carry out the indicated temperature conversions.

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Answer:

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Explanation:

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4 years ago

Which does not affect the rate of pulmonary and systemic gas exchange?

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Answer:b

Explanation:

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3 years ago

How much energy (heat) is required to convert 248 g of water from 0oC to 154oC? Assume that the water begins as a liquid, that t

Arturiano [62]

Answer: The amount of heat required is 775.7 kJ

Explanation:

The processes involved in the given problem are:

$1.)H_2O(s)(0^oC,273K)\rightarrow H_2O(l)(0^oC,273K)\\2.)H_2O(l)(0^oC,273K)\rightarrow H_2O(l)(100^oC,373K)\\3.)H_2O(l)(100^oC,373K)\rightarrow H_2O(g)(100^oC,373K)\\4.)H_2O(g)(100^oC,373K)\rightarrow H_2O(g)(154^oC,427K)$

Now, we calculate the amount of heat released or absorbed in all the processes.

For process 1:

$q_1=m\times L_f$

where,

$q_1$ = amount of heat absorbed = ?

m = mass of water or ice = 248 g

$L_f$ = latent heat of fusion = 334 J/g

Putting all the values in above equation, we get:

$q_1=248g\times 334J/g=84832J$

For process 2:

$q_2=m\times C_{p,l}\times (T_{2}-T_{1})$

where,

$q_2$ = amount of heat absorbed = ?

$C_{p,l}$ = specific heat of water = 4.184 J/g°C

m = mass of water = 248 g

$T_2$ = final temperature = $100^oC$

$T_1$ = initial temperature = $0^oC$

Putting all the values in above equation, we get:

$q_2=248g\times 4.184J/g^oC\times (100-0)^oC=103763.2J$

For process 3:

$q_3=m\times L_v$

where,

$q_3$ = amount of heat absorbed = ?

m = mass of water or ice = 248 g

$L_v$ = latent heat of vaporization = $40.79kJ/mol\times \frac{1000}{18}=2266.1J/g$ (Conversion factor used: 1 kJ = 1000 J and molar mass of water = 18 g/mol)

Putting all the values in above equation, we get:

$q_3=248g\times 2260J/g=560480J$

For process 4:

$q_4=m\times C_{p,g}\times (T_{2}-T_{1})$

where,

$q_4$ = amount of heat absorbed = ?

$C_{p,g}$ = specific heat of steam = 1.99 J/g°C

m = mass of water = 248 g

$T_2$ = final temperature = $154^oC$

$T_1$ = initial temperature = $100^oC$

Putting all the values in above equation, we get:

$q_4=248g\times 1.99J/g^oC\times (154-100)^oC=26650.1J$

Calculating the total heat absorbed, we get:

$Q=q_1+q_2+q_3+q_4$

$Q=[84832+103763.2+560480+26650.1]J=775,725.3J=775.7kJ$

Hence, the amount of heat required is 775.7 kJ

5 0

4 years ago

five atoms of hydrogen are reactants in a chemical reaction. how many atoms of hydrogen will be found in the products of that re

Mkey [24]

Answer:

5 atoms of hydrogen will be found in the products

Explanation:

5 atoms of hydrogen will be found in the products becuase the law of conservation of mass states that mass is neither created nor destroyed in chemical reactions.

6 0

3 years ago

What is one group of people or animals that are impacted by ocean acidification?

ki77a [65]

Answer:

Impacts on Ocean Life

Coral Reefs.

Oysters, Mussels, Urchins and Starfish.

Zooplankton.

Plants and Algae.

Fish.

Explanation:

6 0

3 years ago

Read 2 more answers