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Stels [109]
3 years ago
12

How does a buffer resist change in pH upon addition of a strong acid? The strong acid reacts with the strong base in the buffer

to form a salt, which produces few H+ ions in solution and therefore only a little change in pH. The strong acid reacts with the weak base in the buffer to form a weak acid, which produces few H+ ions in solution and therefore only a little change in pH. The strong acid reacts with the weak acid in the buffer to form a weak base, which produces few H+ ions in solution and therefore only a little change in pH.
Chemistry
1 answer:
MrRa [10]3 years ago
4 0

Answer:

The strong acid reacts with the weak base in the buffer to form a weak acid, which produces few H+ ions in solution and therefore only a little change in pH.

Explanation:

When a strong acid is added to the buffer, the acid dissociates and furnish hydrogen ions which combine with the conjugate of the weak acid, forming weak acid. The weak acid dissociates to only some extent and can furnish only some protons and there is no significant change in the pH.

Hence, option B is correct.

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How many electrons in an atom could have these sets of quantum numbers? n=2?
slavikrds [6]
A maximum of 8 electrons can share the quantum number  n = 2.

Principal Quantum number has a symbol of "n". It tells you the energy level on which an electron resides. Y<span>ou need to determine exactly how many </span>orbitals<span> you have in this energy level before you can determine the number of electrons that can share the value of n.
</span>

The number of orbitals you get per energy level can be found using this formula:

<span>no. of orbitals=<span>n</span></span><span>²</span>

Each orbital can hold a maximum of two electrons, the formula would be:

<span>no. of electrons=2<span>n</span></span><span>²</span>

Using the given formulas:

<span>no. of orbitals = <span>n</span></span><span>² </span><span>= </span><span>2</span><span>² </span><span>= </span><span>4</span>

<span>no. of electrons </span><span>=</span><span>2 *</span><span> </span><span>4 </span><span>= </span><span>8 </span>




6 0
4 years ago
How many grams of sodium benzoate, C H CO Na, have to be added to 1.50 L of a 0.0200 M solution of benzoic acid, C H CO H, to ma
Dmitrij [34]

Answer: 2.8275grams

Explanation: A buffer is made btw a weak acid and it salt. In a solution made by dissolving a weak acid in solution, equilibrium is set up btw ionised and unionised ion. For Benzoic acid

C6H5COOH....> C6H5COO- + H+

Ka = [C6H5COO-] [H+]/ [C6H5COOH].......(1)

using Ka = 6.5× 10^-5, [C6H5COOH] = 0.02M. PH= - log[H+] ....> [H+]= 10^-4M.

Putting the values in(1)

[C6H5COO-]= 6.5× 10^-5 × 0.02/ 10^-4

[C6H5COO-] = 0.013M = Molarity of sodium benzoate

Mole(C6H5COONa) = 0.013 × Volume = 0.013mol/litre × 1.5 litre

Mole(C6H5COONa) = 0.0195mol

Mass(C6H5COONa) = 0.0195 × Molar mass

Mass(C6H5COONa) = 2.8275g

4 0
4 years ago
What is the molar mass of (NH4)2 CO3
pentagon [3]
96.09 g/mol good luck and give thanks:)
7 0
3 years ago
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3 years ago
You are working in a laboratory, and you are given the task of converting cyclopentene into 1, 5-pentanediol. Your first thought
Helen [10]

Answer:

Reagent A = H_3O^+

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Intermediate C= δ-Valerolactone

Explanation:

In the reaction from the alkene to the alcohol, we can use the <u>alkene hydration</u> in which the hydronium ion is added to the double bond followed by the attack of water to produce the <u>alcohol</u>.

Then in the conversion from alcohol to ketone can be produced if an <u>oxidant reactive</u><u> </u>is used. In this case the <u>Jones reagent </u>( Na_2Cr_2O_7~H_2SO_4~H_2O).

The intermediate is a structure produced by a <u>peroxyacid</u>. This reaction would introduce an <u>ester group </u>in the cycle generating the δ-Valerolactone (Figure 1).

7 0
3 years ago
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