A maximum of 8 electrons can share the quantum number n = 2.
Principal Quantum number has a symbol of "n". It tells you the energy level on which an electron resides. Y<span>ou need to determine exactly how many </span>orbitals<span> you have in this energy level before you can determine the number of electrons that can share the value of n.
</span>
The number of orbitals you get per energy level can be found using this formula:
<span>no. of orbitals=<span>n</span></span><span>²</span>
Each orbital can hold a maximum of two electrons, the formula would be:
<span>no. of electrons=2<span>n</span></span><span>²</span>
Using the given formulas:
<span>no. of orbitals = <span>n</span></span><span>² </span><span>= </span><span>2</span><span>² </span><span>= </span><span>4</span>
<span>no. of electrons </span><span>=</span><span>2 *</span><span> </span><span>4 </span><span>= </span><span>8 </span>
Answer: 2.8275grams
Explanation: A buffer is made btw a weak acid and it salt. In a solution made by dissolving a weak acid in solution, equilibrium is set up btw ionised and unionised ion. For Benzoic acid
C6H5COOH....> C6H5COO- + H+
Ka = [C6H5COO-] [H+]/ [C6H5COOH].......(1)
using Ka = 6.5× 10^-5, [C6H5COOH] = 0.02M. PH= - log[H+] ....> [H+]= 10^-4M.
Putting the values in(1)
[C6H5COO-]= 6.5× 10^-5 × 0.02/ 10^-4
[C6H5COO-] = 0.013M = Molarity of sodium benzoate
Mole(C6H5COONa) = 0.013 × Volume = 0.013mol/litre × 1.5 litre
Mole(C6H5COONa) = 0.0195mol
Mass(C6H5COONa) = 0.0195 × Molar mass
Mass(C6H5COONa) = 2.8275g
96.09 g/mol good luck and give thanks:)
Answer:
Reagent A = 
Reagent B= 
Intermediate C= δ-Valerolactone
Explanation:
In the reaction from the alkene to the alcohol, we can use the <u>alkene hydration</u> in which the hydronium ion is added to the double bond followed by the attack of water to produce the <u>alcohol</u>.
Then in the conversion from alcohol to ketone can be produced if an <u>oxidant reactive</u><u> </u>is used. In this case the <u>Jones reagent </u>(
).
The intermediate is a structure produced by a <u>peroxyacid</u>. This reaction would introduce an <u>ester group </u>in the cycle generating the δ-Valerolactone (Figure 1).