Question

Dwayne Wade made 439 field goals out of 937 attempts. What was Dwayne Wade's ratio of successful field goals to attempt?

Answer 1

Let's set this ratio up as a fraction: (successful field goals)/(field goal attempts)
There were 439 successful field goals and 937 attempts: 439/937
The fraction cannot be reduced, so the ratio is 439/937.

Answer 2

Answer:

$\frac{439}{937}$

Step-by-step explanation:

Given: Dwayne Wade made 439 field goals out of 937 attempts

To Find: Dwayne Wade's ratio of successful field goals to attempt

Solution:

Total field goals made by Dwayne Wade= $439$

Total attempt Dwayne Wade made = $937$

Now,

ratio of successful field goals to attempt made = $\frac{\text{Total successful goals fielded by Dwayne Wade}}{\text{Total attempts}}$

on putting values,

ratio of successful field goals to attempt made = $\frac{439}{937}$

As the fraction can not be simplified more,

Dwayne Wade's ratio of successful field goals to attempt is  $\frac{439}{937}$