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makkiz [27]
3 years ago
11

Which of the following ordered pairs represents the x-intercept of the equation y = 2x - 8?

Mathematics
2 answers:
Lena [83]3 years ago
4 0
Y=2x-8, so ti find the x-intercept, you would plug zero into y and solve for x:

0=2x-8 plug 0 in for y and now add 8 to both sides 
8=2x now you have to divide by 2
4=x
(4,0)
nikdorinn [45]3 years ago
3 0
The answer is (0,-8)
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Answer:

H is the Answer

Step-by-step explanation:

Apply distance formula.

(x {}^{2  } -  {x}^{1}  ) {}^{2}  + ( {y}^{2}  -  {y}^{1} ) {}^{2}  = d {}^{2}

where d is the distance.

( - 5 - 7) {}^{2}  + (0 - 5) {}^{2}  =

- 12 {}^{2}  +  - 5 {}^{2}  =  {d}^{2}

\sqrt{169}  =  {d}^{2}

d = 13

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3 years ago
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victus00 [196]
You have to subtract both sides by 64 and you will get,
-50 = 5z. Then divide both sides by 5, and you get -10 = z.
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3 years ago
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Help please I don’t understand any of this
sveta [45]

The two angles form a straight line which is equal to 180 degrees. This makes the angles supplemtary.

To find x, add the two angles together to equal 180:

7x + x+20 = 180

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Subtract 20 from both sides:

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Guys please help me out ASAP, Due today. I
Mice21 [21]

Answer:

T_7 = 11

T_n = 2n- 3

Step-by-step explanation:

Given

S_n = n^2 -2n

T_n = S_n - S_{n-1}

Solving (a): T7

Substitute 7 for n in T_n = S_n - S_{n-1}

T_7 = S_7 - S_{7-1}

T_7 = S_7 - S_6

Calculate S7 and S6

S_n = n^2 -2n

S_7 = 7^2 - 2 * 7 = 35

S_6 = 6^2 - 2 * 6 = 24

So:

T_7 = 35 -24

T_7 = 11

Solving (b): Tn

T_n = S_n - S_{n-1}

Where S_n = n^2 -2n

CalculateS_{n-1}

We have:

S_{n-1} =(n-1)^2 - 2(n-1)

Open brackets

S_{n-1} = n^2 -2n + 1 -2n +2

S_{n-1} = n^2 -2n-2n + 1  +2

S_{n-1} = n^2 -4n + 3

So:

T_n = S_n - S_{n-1}

T_n = n^2 - 2n - (n^2 -4n + 3)

T_n = n^2 - 2n - n^2 +4n - 3

Collect Like Terms

T_n = n^2 - n^2- 2n  +4n - 3

T_n = 2n- 3

5 0
3 years ago
Some steps to construct an angle MNT congruent to angle PQR are listed below. Step 3 is not listed:
katrin [286]

Answer: D. Maintaining the same width of the compass as AB, draw an arc from point X such that it intersects the arc drawn from N in a point Y.

Took the test.

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