For this problem, we use the Coulomb's law written in equation as:
F = kQ₁Q₂/d²
where
F is the electrical force
k is a constant equal to 9×10⁹
Q₁ and Q₂ are the charge of the two objects
d is the distance between the two objects
Substituting the values:
F = (9×10⁹)(-22×10⁻⁹ C)(-22×10⁻⁹ C)/(0.10 m)²
F = 0.0004356 N
Answer:
7.535×10^25 earth mass
Explanation:
for an approximate result,divide the mass value by 9.223e+18
Explanation:
The given data is as follows.
Electric potential energy () = ?
Formula to calculate electric potential energy is as follows.
=
=
Thus, we can conclude that the electric potential energy of the pair of charges when the second charge is at point b is .