Which statement describes how a covalent molecule would be formed?

The speed of light is 3 x 108 m/s (300,000,000 m/s). A light wave has a wavelength of 400 nm (0.0000004 m). What is the frequenc

kirill115 [55]

Explanation:

velocity = wavelength × frequency

3×10⁸ = 400/10⁹ × frequency

frequency = 3 × 10¹⁵ /400

frequency = 75×10¹¹Hz

6 0

2 years ago

At a certain altitude above the Earth's surface, the electric field has a magnitude of 135 V/m. How much energy is stored in 1.0

Paul [167]

Answer:

Explanation:

Given that,

Electric field E=135V/m

Energy stored in 1m³of air=?

The energy stored in an electric field is given as

u = ½ εo E²

Where

U is the energy stored

εo is permissivity and it value is 8.85×10^-12C²/N..m²

And E is the electric field

Then,

U=½×8.85×10^-12×135²

U=8.06×10^-8J/m³

Then, the energy stored in 1m³ of air is 8.06×10^-8 J/m³

4 0

3 years ago

Can the momentum of an object change

OlgaM077 [116]

The answer for this is yes.

8 0

4 years ago

Read 2 more answers

deon is running at a velocity of 7.9 meters per second. deon has a total mass of 95 kilograms including his helmet, uniform, pad

brilliants [131]

Answer:

712.5 kg m/s

Explanation:

Work out the total momentum before the event (before the collision):

p = m × v

Massof Deon = 95kg

Velocity =7.5m/s

Mass of Chuck = 120kg

Velocity = 0m/s

Momentum of Deon before = 95 × 7.5 = 712.5 kg m/s

Momentum of Chuck before = 120 × 0 = 0 kg m/s

Total momentum before = 712.5+ 0 = 712.5 kg m/s

Working out the total momentum after the event (after the collision):

Because momentum is conserved, total momentum afterwards = 712.5 kg m/s

6 0

3 years ago

A particle moves along the x axis. It is initially at the position 0.270 m, moving with velocity 0.140 m/s and acceleration 20.3

mixas84 [53]

Answer:

a) -2.34 m

b) -1.3 m/s

c) 0.056 m

d) 0.320 m/s

Explanation:

part a

Given:

s(0) = 0.27 m

v(0) = 0.14 m/s

a = -0.320 m/s^2

t = 4.50s

Using kinematic equation of motion for constant acceleration:

s (t) = s(0) + v(0)*t + 0.5*a*t^2

s ( 4.5 s ) = 0.27 + 0.14*4.5 + 0.5*-0.32*4.5^2

s(4.5) = -2.34 m

part b

Using kinematic equation of motion for constant acceleration:

v(t) = v(0) + a*t

v(4.5s) = (0.14) + (-0.32)(4.5) = -1.3 m/s

part c

Use equation for simple harmonic motion:

s(t) = A*cos(w*t)

v(t) = -A*w*sin (w*t)

a(t) = -A*(w)^2 * cos (w*t)

0.27 m = A*cos(w*t) .... Eq 1

0.14 m/s = - A*w*sin (w*t) .....Eq2

-0.320 = -A*(w)^2 * cos (w*t) .... Eq3

Solve the three equations above for A, w, and t

Divide 1 and 3:

w^2 = 0.32 / 0.27

w = 1.0887 rad / s

Divide 2 and 1:

w*tan(wt) = 0.14 / 0.27

tan(1.0887*t) = 0.476289

t = 0.4083 s

A = 0.27 / cos (1.0887*0.4083) = 0.3 m

Hence, the SHM is s(t) = 0.3*cos(1.0887*t)

s(4.5) = 0.3*cos(1.0887*4.5) = 0.056 m

part d

v(t) = - 0.32661 * sin (1.0887*t)

v(4.5) = - 0.32661 * sin (1.0887*4.5) = 0.320 m/s

3 0

3 years ago