From Gauss law we have
E = 2kx/r where x=linear charge density, r=distance from the wire=1.7 m
k =9 x 10^9 SI units.....we have been given E = 3.8 x 10^4 N/C ..... so plugging numbers we get
x = 3.59 x 10^ -6 C/ M (coulomb per meter) =linear charge density
Answer:
This formula R =ρL/A
Where R = resistance of wire, ρ = resistivity of the wire and A = area of the wire. Shows there is an inverse relationship between Resistance and Area of the wire.
Explanation:
A simple way to explain the physics behind such an electrical code is to compare the flow of current through wires to the flow of water through pipes, they are similar in any respect. The resistance to the flow of current in an electric circuit is similar to the frictional experienced by water when flowing through water pipes. Just as water will flow easily with little resistance through a water pipe with the larger cross-sectional area than one with a smaller cross-sectional area, in the same way, wires with larger cross-sectional area will allow the flow of larger amount of current compared to wires with smaller cross-sectional area assuming all other variables are the same.
From the formula R =ρL/A
Where R = resistance of wire, ρ = resistivity of the wire and A = area of the wire
We can see that the resistance and area of the wire have an inverse relationship. An increase in the area of the wire will lead to a decrease in the resistance of the wire.
Answer:
0.098 N
Explanation:
From the question,
Spring scale reading = W-U............... Equation 1
Where W = weight of the cube, U = upthrust.
W = mg
Where m = mass of the cube, g = acceleration due to gravity.
Given: m = 11 g = 0.011 kg, g = 9.8 m/s².
W = 0.011(9.8)
W = 0.1078 N.
From Archimedes principle,
Upthrust = weight of water displaced.
U = (Density of water×volume of metal cube)×acceleration due to gravity.
U = (D×V)g
Given: D = 1000 kg/m², V = 1 cm³ = (1/1000000) = 1×10⁻⁶ m³, g - 9.8 m/s²
U = 1000(9.8)(10⁻⁶)
U = 0.0098 N.
Substitute the value of W and U into equation 1
Reading of the spring scale = 0.1078-0.0098
Reading of the spring scale = 0.098 N
Answer:
Explanation:
Let the balls collide after time t .
distance covered by falling ball
s₁ = v₀ t + 1/2 g t²
distance covered by rising ball
s₂ = v₀ t - 1/2 g t²
Given ,
s₁ + s₂ = D
D = v₀ t + 1/2 g t² + v₀ t - 1/2 g t²
= 2v₀ t
t = D / 2v₀
s₂ = v₀ t - 1/2 g t²
= v₀ x D / 2v₀ - (1/2) x g x D² / 4v₀²
= D / 2 - gD² / 8 v₀²
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