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3 years ago

I need help FAST!!! It’s on my grade

Physics

1 answer:

Stells [14]3 years ago

3 0

Solar energy, because of solar panels, hydroelectricity from a dam, or fossil fuels. fossil fuels would be the most ideal because it is more commonly used

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What is sex ansd asexual.

Nata [24]

This might help and best of wishes!

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3 years ago

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Which of the following statements is NOT true?

Nataly [62]

I think it’s D but i’m not too sure

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3 years ago

Momentum of an object is determined to be 7.2 ×10 to the negative 3 kg

abruzzese [7]

Answer:

0.0072

Explanation

7.2x10^-3= 0.0072

6 0

2 years ago

In 1610, galileo used his telescope to discover four prominent moons around jupiter. their mean orbital radii a and periods t ar

katrin2010 [14]

Time period of any moon of Jupiter is given by

$T = 2\pi \sqrt{\frac{r^3}{GM}}$

from above formula we can say that mass of Jupiter is given by

$M = \frac{4 \pi^2 r^3}{GT^2}$

now for part a)

$r = 4.22 * 10^8 m$

T = 1.77 day = 152928 seconds

now by above formula

$M = \frac{4 \pi^2 r^3}{GT^2}$

$M = \frac{4 \pi^2 (4.22 * 10^8)^3}{(6.67 * 10^{-11})(152928)^2}$

$M = 1.9* 10^{27} kg$

Part B)

$r = 6.71 * 10^8 m$

T = 3.55 day = 306720 seconds

now by above formula

$M = \frac{4 \pi^2 r^3}{GT^2}$

$M = \frac{4 \pi^2 (6.71 * 10^8)^3}{(6.67 * 10^{-11})(306720)^2}$

$M = 1.9* 10^{27} kg$

Part c)

$r = 10.7 * 10^8 m$

T = 7.16 day = 618624 seconds

now by above formula

$M = \frac{4 \pi^2 r^3}{GT^2}$

$M = \frac{4 \pi^2 (10.7 * 10^8)^3}{(6.67 * 10^{-11})(618624)^2}$

$M = 1.89* 10^{27} kg$

PART D)

$r = 18.8 * 10^8 m$

T = 16.7 day = 1442880 seconds

now by above formula

$M = \frac{4 \pi^2 r^3}{GT^2}$

$M = \frac{4 \pi^2 (18.8 * 10^8)^3}{(6.67 * 10^{-11})(1442880)^2}$

$M = 1.889* 10^{27} kg$

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3 years ago

A metaphysical poet is a writer whose

EastWind [94]

Not really sure but...

<span>A metaphysical poet is a writer whose </span>focus is on universal human experiences.
hope this helps!...

8 0

3 years ago