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3 years ago

Find the quotient and enter your answer in the box below. 617/10^2

Mathematics

2 answers:

Bad White [126]3 years ago

5 0

Answer:

6.17

Step-by-step explanation:

This is how I worked it out:

617 ÷ 10^2

617 ÷ 100

= 6.17

Just in case, I'll explain what the 10^2 means. That is 10 to the second power, or 10 squared, but when you type it, you cannot make the 2 go where it needs to be as it is written, unless you use an equation builder. So, 10 squared becomes 10^2.

10^2 means 10 multiplied by itself. So, 10 × 10 = 100. Then, all you have to do is divide 617 by 100. You could simply move the decimal of the 617 left two places or use a calculator.

Serggg [28]3 years ago

3 0

Answer:

6.17

Step-by-step explanation:

617/10^2 = 617/100 = 6.17

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A local bakery buys their flour in bulk. The relationship between the cost of the flour and its weight is shown in the graph bel

Nataly [62]

The relationship shown for the flour and the cost is that of a direct variation because the graph is a straight line, noting that the increase of one variable causes also the increase to the value of the other. The point (1, 0.75) means that every pound of flour costs 0.75 dollar. From the graph given, the bakery will have to pay approximately $30 for 40 pounds of flour.

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4 years ago

Find the arc length of the given curve between the specified points. x = y^4/16 + 1/2y^2 from (9/16), 1) to (9/8, 2).

lutik1710 [3]

Answer:

The arc length is $\dfrac{21}{16}$

Step-by-step explanation:

Given that,

The given curve between the specified points is

$x=\dfrac{y^4}{16}+\dfrac{1}{2y^2}$

The points from $(\dfrac{9}{16},1)$ to $(\dfrac{9}{8},2)$

We need to calculate the value of $\dfrac{dx}{dy}$

Using given equation

$x=\dfrac{y^4}{16}+\dfrac{1}{2y^2}$

On differentiating w.r.to y

$\dfrac{dx}{dy}=\dfrac{d}{dy}(\dfrac{y^2}{16}+\dfrac{1}{2y^2})$

$\dfrac{dx}{dy}=\dfrac{1}{16}\dfrac{d}{dy}(y^4)+\dfrac{1}{2}\dfrac{d}{dy}(y^{-2})$

$\dfrac{dx}{dy}=\dfrac{1}{16}(4y^{3})+\dfrac{1}{2}(-2y^{-3})$

$\dfrac{dx}{dy}=\dfrac{y^3}{4}-y^{-3}$

We need to calculate the arc length

Using formula of arc length

$L=\int_{a}^{b}{\sqrt{1+(\dfrac{dx}{dy})^2}dy}$

Put the value into the formula

$L=\int_{1}^{2}{\sqrt{1+(\dfrac{y^3}{4}-y^{-3})^2}dy}$

$L=\int_{1}^{2}{\sqrt{1+(\dfrac{y^3}{4})^2+(y^{-3})^2-2\times\dfrac{y^3}{4}\times y^{-3}}dy}$

$L=\int_{1}^{2}{\sqrt{1+(\dfrac{y^3}{4})^2+(y^{-3})^2-\dfrac{1}{2}}dy}$

$L=\int_{1}^{2}{\sqrt{(\dfrac{y^3}{4})^2+(y^{-3})^2+\dfrac{1}{2}}dy}$

$L=\int_{1}^{2}{\sqrt{(\dfrac{y^3}{4}+y^{-3})^2}dy}$

$L= \int_{1}^{2}{(\dfrac{y^3}{4}+y^{-3})dy}$

$L=(\dfrac{y^{3+1}}{4\times4}+\dfrac{y^{-3+1}}{-3+1})_{1}^{2}$

$L=(\dfrac{y^4}{16}+\dfrac{y^{-2}}{-2})_{1}^{2}$

Put the limits

$L=(\dfrac{2^4}{16}+\dfrac{2^{-2}}{-2}-\dfrac{1^4}{16}-\dfrac{(1)^{-2}}{-2})$

$L=\dfrac{21}{16}$

Hence, The arc length is $\dfrac{21}{16}$

6 0

3 years ago

Write a story problem to go with the multiplication problem 4 x 2/3 Then, solve the problem. PLEASE HELP ASAP

Maru [420]

Answer:8/3x

Step-by-step explanation:tell if this didnt work

5 0

2 years ago

7x ^4 minus 5x ^4 =

lapo4ka [179]

Answer:

2x^{4}

Step-by-step explanation:

You would subtract 7 and 5 and you would leave the exponent so it would be 2x^{4}

8 0

3 years ago

Read 2 more answers

Simplify for a lot of points<br> (1-sin^2x)(1-tan^2x)

notka56 [123]

1/sin^2x-1/tan^2x=
1/sin^2x-1/ (sin^2x/cos^2x)<<sin tan= sin/cos>>
= 1/sin^2x- cos^2x / sin^2x
= (1- cos^2x) / sin^2x <<combining into a single fraction>>
sin^2 x / sin^2x <<since 1- cos^2 x sin^2 x

=1
this simplifies to 1.

6 0

4 years ago