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Elenna [48]
2 years ago
12

PLEASE HELP!! Find the area of the square

Mathematics
2 answers:
Airida [17]2 years ago
5 0
Well they U the answer so....
I'll take the extra pts ty
aniked [119]2 years ago
4 0

\sf \bigstar \:  \red{Answer :-}

We have been provided :-

  • Length of a side of a square = \sf \: 5 {a}^{6}

We know that,

\bigstar \: \boxed{\sf \red{area \: of \: a \: square \:  = side \times side}}

Therefore, to find the area we will simply put the given values in the equation.

So,

\sf  \: area =  {5a}^{6}  \times  {5a}^{6}  =   {5a}^{6 + 6}  =  {5a}^{12}

<u>❆ Some important identities to remember</u> :-

\longrightarrow\sf \:  {a}^{m}  \times  {a}^{n}  =  {a}^{m + n}  \\    \longrightarrow\sf \: {a}^{m}  \times  {b}^{m}  =  {ab}^{m}  \:  \\   \longrightarrow\sf \: {a}^{m}  \div  {a}^{n}  =  {a}^{m - n}

Hope that helps :)

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Please show all your work!!!
Alex73 [517]

Answer:

y= -6/5x -3

Step-by-step explanation:

So for now lets bring it into mx + b format

Subtract 6x from both sides to isolate y which is also called subtraction property of equality.

so 5y = -6x -15

Now you divide both sides by 5 which is called division property of equality.

You now have y = -6/5x - 3

y= -6/5x -3 is the slope intercept form of the standard form equation of 6x + 5y = -15.

Hope this helps!

3 0
2 years ago
If ps=6cm and pt=9cm what is pr
vladimir1956 [14]

16+  x^{2}  = 36&#10;
x^{2} =20
x= \sqrt{20}
4^{2} + x^{2} =  6^{2} &#10;

Hope it helps!
#MissionExam001
4 0
3 years ago
What is the answer to 3 1/3=5a please show work
marshall27 [118]
it is 3 divided by 31 then subtract 31 with 30 which will give you 10R1

7 0
3 years ago
The endpoints of (MP)are M(2,1) and P(12,6). If point K partitions (MP) in a ratio of MK:KP = 3:2, what are the coordinates of K
GREYUIT [131]

Answer:

K(8, 4)

Step-by-step explanation:

Given:

M(2, 1), P(12, 6)

MK:KP = 3:2

Required:

Coordinates of K

SOLUTION:

Coordinates of K can be determined using the formula below:

x = \frac{mx_2 + nx_1}{m + n}

y = \frac{my_2 + ny_1}{m + n}

Where,

M(2, 1) = (x_1, y_1)

P(12, 6) = (x_2, y_2)

m = 3, n = 2

Plug in the necessary values to find the coordinates of K:

x = \frac{mx_2 + nx_1}{m + n}

x = \frac{3(12) + 2(2)}{3 + 2}

x = \frac{36 + 4}{5}

x = \frac{40}{5}

x = 8

y = \frac{my_2 + ny_1}{m + n}

y = \frac{3(6) + 2(1)}{3 + 2}

y = \frac{18 + 2}{5}

y = \frac{20}{5}

y = 4

The coordinates of K = (8, 4)

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=3%5Csqrt%7B5%7D" id="TexFormula1" title="3\sqrt{5}" alt="3\sqrt{5}" align="absmiddle" class="l
adoni [48]

Answer:

3/5???

Step-by-step explanation:

6 0
3 years ago
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