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Dmitry [639]
3 years ago
11

PLEASE HELP I SWEAR I WILL GIVE 50 POINTS AND BRAINLIEST

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
6 0

Answer:

No it doesnt and if you did have an outlier it would greatly affect the mean because if there was an outlier the mean would move closer to the outlier.

Step-by-step explanation:


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5.
rosijanka [135]

Answer:

D 714

Step-by-step explanation:

210 times 3.40

is 714

4 0
2 years ago
Find the limit. (If an answer does not exist, enter DNE.) lim Δx→0 (x + Δx)2 − 3(x + Δx) + 2 − (x2 − 3x + 2) Δx
yawa3891 [41]

\displaystyle\lim_{\Delta x\to0}\frac{(x+\Delta x)^2-3(x+\Delta x)+2-(x^2-3x+2)}{\Delta x}

Expand the numerator as

x^2+2x\Delta x+(\Delta x)^2-3x-3\Delta x+2-x^2+3x-2=(2x-3)\Delta x+(\Delta x)^2

Then in the limit,

\displaystyle\lim_{\Delta x\to0}\frac{(2x-3)\Delta x+(\Delta x)^2}{\Delta x}=\lim_{\Delta x\to0}(2x-3+\Delta x)=\boxed{2x-3}

3 0
2 years ago
There are many regulations for catching lobsters off the coast of New England including required permits, allowable gear, and si
Georgia [21]

Answer:

Probability that the sample mean carapace length is more than 4.25 inches = 0.9993

Step-by-step explanation:

Given - There are many regulations for catching lobsters off the coast

             of New England including required permits, allowable gear, and

             size prohibitions. The Massachusetts Division of Marine Fisheries

             requires a minimum carapace length measured from a rear eye

             socket to the center line of the body shell. For a particular local

             municipality, any lobster measuring less than 3.37 inches must

             be returned to the ocean. The mean carapace length of the  

             lobsters is 4.01 inches with a standard deviation of 2.13 inches.

             A random sample of 60 lobsters is obtained.

To find - What is the probability that the sample mean carapace length

              is more than 4.25 inches?

Proof -

Given that, μ = 4.01, σ = 2.13 , n = 60

Now,

μₓ⁻ = σ / √n

    = \frac{2.13}{\sqrt{60} }

    = \frac{2.13}{7.746} = 0.275

⇒μₓ⁻ = 0.275

Now,

P(X⁻ > 3.37) = 1 - P( X⁻ <  3.37)

                   = 1 - P(z <  \frac{3.37 - 4.25}{0.275} )

                   = 1 - P( z < -3.2 )

                   = 1 - 0.0007

                   = 0.9993

⇒P(X⁻ > 3.37) = 0.9993

∴ we get

Probability that the sample mean carapace length is more than 4.25 inches = 0.9993

6 0
2 years ago
Simplify (4/5)^-2 . Show your work!
jarptica [38.1K]

Answer:

\frac{25}{16}

Step-by-step explanation:

Apply exponent rule: x^{-y}=\frac{1}{x^y}

(\frac{4}{5}) ^{-2}=\frac{1}{\left(\frac{4}{5}\right)^2}=\frac{1}{\frac{16}{25}}=\frac{25}{16}

5 0
3 years ago
What is the solution?<br><img src="https://tex.z-dn.net/?f=%5Clim_%7Bx%5Cto%200%7D%20%5Cfrac%7Bx%20%2B%202%7D%7B%20x%20-2%7D" id
zhenek [66]

Answer:

- 1

Step-by-step explanation:

\lim_{x\to 0} \frac{x + 2}{ x -2}

= \frac{0 + 2}{ 0 -2}

= \frac{2}{-2}

= - 1

5 0
2 years ago
Read 2 more answers
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