4 red, 3 blue, 3 yellow ....total = 10
P(red) = 4/10 reduces to 2/5
without replacement
P(blue) = 3/9 reduces to 1/3
without replacement
P(red) = 3/8
P( all this happens) = 2/5 * 1/3 * 3/8 = 6 / 120 reduces to 1/20 <=
Answer:
45°
Step-by-step explanation:
70mm times 99mm which gets you to 6390mm
or
210mm times 297mm = 62370mm squared
Answer:
The sidewalk is 2 feet wide
Step-by-step explanation:
The area of the sidewalk is given as 80 square feet
The length and width of pool
including side walks will be;
10 + 2x and 6 + 2x
To get the area of the side walk
That will be area of total minus area of the pool
That will be ;
(10 + 2x)(6 + 2x) - 10(6) = 80
60 + 12x + 20x + 4x^2 - 60 = 80
4x^2 + 32x -80 = 0
x^2 + 8x -20
x^2 + 10x - 2x - 20 = 0
x(x + 10) -2(x + 10) = 0
(x-2)(x + 10) = 0
x = 2 or -10
since width cannot be negative;
The sidewalk is 2 feet wide
Answer:
<h2>35 different ways</h2>
Step-by-step explanation:
Since there are 7 students in a classroom to fill a front row containing 3 seats, we will apply the combination rule since we are to select 3 students from the total number of 7 students in the class.
In combination,<em> if r objects are to be selected from a pool of n objects, this can be done in nCr number of ways.</em>
<em>nCr = n!/(n-r!)r!</em>
Selecting 3 students from 7 students to fill the seats can therefore be done in 7C3 number of ways.
7C3 = 7!/(7-3)!3!
7C3 = 7!/(4)!3!
7C3 = 7*6*5*4!/4!*3*2
7C3 = 7*6*5/6
7C3 = 7*5
7C3 = 35
<em>Hence there are 35 different ways that the student can sit in the front assuming there are no empty seats.</em>
