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Nana76 [90]
3 years ago
13

How to solve system of equations khan academy?

Mathematics
1 answer:
Tamiku [17]3 years ago
7 0
You can use the elimination method.

You can have y crossed out so you can solve for x and then have x crossed out to solve for y for instance:

X - y = 8
+
X +y =4

To have y gone we have to make it equal to y - y or in this case -y + +y
So
X - y = 8
+
X + y = 4

2x = 12
———-
2. 2

X=6

Now to find y we have x crossed out.

X-y=8
X+y=4

To have x crossed out we’d do x - x
So

X-y = 8
-
X+ y = 4

-2y = 4
————-
-2. -2

Y = -2

Since coordinates go like (x,y) the system of equations for this problem is (6, -2)
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The equation in the given standard form is (x+10)^2+(y+6)^2=5^2

<h3>Equation of a circle</h3>

The standard equation of a circle is expressed as:

(x-a)^2+(y-b)^2=r^2

Given the equation x^2 + y^2 + 20x + 12y + 111 =0

Group the function to have:

(x^2 +20x)+(y^2+ 12y) + 111 =0

Complete the squares to have:

(x^2 +20x)+(y^2+ 12y) + 111 =0\\(x^2+20x+10^2-10^2)+(y^2+12y+6^2-6^2)+111=0\\(x+10)^2+(y+6)^2 -100-36+111=0\\(x+10)^2+(y+6)^2-25=0\\(x+10)^2+(y+6)^2=25\\(x+10)^2+(y+6)^2=5^2

Hence the equation in the given standard form is (x+10)^2+(y+6)^2=5^2

Learn more on equation of a circle here: brainly.com/question/1506955

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