the complete question in the attached figure
statements
case A) f(15)=8-----> is correct
for x=15
f(x)=8
case B) the domain of f(x) is the set {5,6,7,8,10,11,12,13}--> is not correct
because the domain of f(x) is the set {0,5,10,15,20,25,30,35,40}
case C) f(5)=6-----> is correct
for x=5
f(x)=6
case D) the range for f(x) is all real numbers----> is not correct
because
the range of f(x) is the set {5,6,7,8,9,10,11,12,13}
the answer is
A and C
Answer: A, B, C, D
Step-by-step explanation:
A. This is true because all rhombi are parallelograms, and diagonals of a parallelogram bisect each other.
B. This is true because the diagonals of a rhombus are perpendicular.
C. This is true because diagonals of a rhombus bisect the angles from which they are drawn,
D. This is true because all sides of a rhombus are congfruent.
E. This is not always true - all rhombi are parallelograms, and adjacent angles of a parallelogram are supplementary, but not always congruent.
F. This is not always true - diagonals of a rhombus are not always congruent.
Answer:
Price of CD player = $96
Step-by-step explanation:
Given:
Sales tax = 5%
Amount of sales tax = $4.80
Find:
Price of CD player
Computation:
Price of CD player = Amount of sales tax / Sales tax
Price of CD player = 4.8 / 5%
Price of CD player = $96
The correct answer is: [B]: " (2, 5) ".
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Given:
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-5x + y = -5 ;
-4x + 2y = 2 .
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Consider the first equation:
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-5x + y = -5 ; ↔ y + (-5x) = -5 ;
↔ y - 5x = -5 ; Add "5x" to each side of the equation; to isolate "y" on one side of the equation; and to solve in terms of "y".
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y - 5x + 5x = -5 + 5x
y = -5 + 5x ; ↔ y = 5x - 5 ;
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Now, take our second equation:
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-4x + 2y = 2 ; and plug in "(5x - 5)" for "y" ; and solve for "x" :
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-4x + 2(5x - 5) = 2 ;
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Note, 2(5x - 5) = 2(5x) - 2(5) = 10x - 10 ;
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So: -4x + 10x - 10 = 2 ;
On the left-hand side of the equation, combine the "like terms" ;
-4x +10x = 6x ; and rewrite:
6x - 10 = 2 ;
Now, add "10" to each side of the equation:
6x - 10 + 10 = 2 + 10 ;
to get:
6x = 12 ; Now, divide EACH side of the equation by "6" ; to isolate "x" on one side of the equation; and to solve for "x" ;
6x/6 = 12 / 6 ;
x = 2 ;
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Now, take our first given equation; and plug our solved value for "x" ; which is "2" ; and solve for "y" ;
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-5x + y = -5 ;
-5(2) + y = -5 ;
-10 + y = -5 ; ↔
y - 10 = -5 ;
Add "10" to each side of the equation; to isolate "y" on one side of the equation; and to solve for "y" ;
y - 10 + 10 = -5 + 10 ;
y = 5 .
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So, we have, x = 2 ; and y = 5 .
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Now, let us check our work by plugging in "2" for "x" and "5" for "y" in BOTH the original first and second equations:
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first equation:
-5x + y = -5 ;
-5(2) + 5 =? -5?
-10 + 5 =? -5 ? YES!
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second equation:
-4x + 2y = 2 ;
-4(2) + 2(5) =? 2 ?
-8 + 10 =? 2 ? Yes!
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So, the answer is:
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x = 2 , y = 5 ; or, "(2, 5)" ; which is: "Answer choice: [B] " .
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