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Nana76 [90]
3 years ago
13

How to solve system of equations khan academy?

Mathematics
1 answer:
Tamiku [17]3 years ago
7 0
You can use the elimination method.

You can have y crossed out so you can solve for x and then have x crossed out to solve for y for instance:

X - y = 8
+
X +y =4

To have y gone we have to make it equal to y - y or in this case -y + +y
So
X - y = 8
+
X + y = 4

2x = 12
———-
2. 2

X=6

Now to find y we have x crossed out.

X-y=8
X+y=4

To have x crossed out we’d do x - x
So

X-y = 8
-
X+ y = 4

-2y = 4
————-
-2. -2

Y = -2

Since coordinates go like (x,y) the system of equations for this problem is (6, -2)
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Answer:

a. a(b)c  

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Step-by-step explanation:

We are given the following in the question:

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a. a(b)c

It is given b belongs to W.

b \in W\\\Rightarrow a(b)c \in W

b. a(a(b)c)c

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a(abc)c does not belong to W because we cannot find x in W such that a(abc)c belongs to W.

d. a(a(a(a)c)c)c

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e. a(aacc)c

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Answer:

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Step-by-step explanation:

Vertical angles share a vertex and have opposite rays for sides.

Rays AE and AB are opposite; rays AG and AC are opposite. These are the only pairs of opposite rays in the figure, so the vertical angles must be constructed from one of the rays of the first pair and one of the rays of the second pair. ∠EAG and ∠BAC are a pair of vertical angles.

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