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Evgesh-ka [11]
3 years ago
5

A−9=6 addition equation.

Mathematics
2 answers:
wel3 years ago
6 0

Answer:  *A=15* is the answer

 

Step-by-step explanation:

Hope this helps!

blondinia [14]3 years ago
4 0

Answer:

15

Step-by-step explanation:

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To gain a pass a student needs to achieve a mean of at least 60% in eight tests. In the first seven
Tanzania [10]

Step-by-step explanation:

the mean value is the sum of all data points divided by the number of data points.

first we have 7 tests and their mean value :

(t1 + t2 + t3 + t4 + t5 + t6 + t7) / 7 = 54

that means

(t1 + t2 + t3 + t4 + t5 + t6 + t7) = 54 × 7 = 378

in order for the mean value to be at least 60% after 8 tests, we need to add a t8, so that

(t1 + t2 + t3 + t4 + t5 + t6 + t7 + t8) = 60 × 8 = 480

because only then we have

(t1 + t2 + t3 + t4 + t5 + t6 + t7 + t8) / 8 = 60

and the student passes.

so,

(t1 + t2 + t3 + t4 + t5 + t6 + t7) + t8 = 480

378 + t8 = 480

t8 = 480 - 378 = 102%

the student would have to achieve 102% on the 8th test.

which would be normally impossible, but maybe the tests involve some bonus points.

6 0
2 years ago
Drag the tiles to the boxes to form correct pairs
sergiy2304 [10]

( -  \frac{3}{4} )( \frac{7}{8} )

=  \frac{ - 3}{4}  \times  \frac{7}{8}

=  \frac{ - 21}{32}

_______________________________________

( \frac{2}{3} )( - 4)(9)

=  \frac{2}{3}  \times  - 4 \times 9

=  \frac{ - 72}{3}

=  - 24

_______________________________________

( \frac{5}{16} )( - 2)( - 4)( -  \frac{4}{5} )

=  \frac{5}{16}  \times  - 2 \times  - 4 \times  \frac{ - 4}{5}

=  \frac{ - 160}{80}

=  \frac{ - 16}{8}

=  - 2

_______________________________________

(2 \frac{3}{5} )( \frac{7}{9} )

=  \frac{13}{5}  \times  \frac{7}{9}

=  \frac{91}{45}

3 0
3 years ago
HELP ME PLEASE <br> Again lol
KatRina [158]
False
true
false
i could be wrong but i’m 85% certain
4 0
2 years ago
Find the 8th term of the G.P 9,3,1,​
son4ous [18]

Answer:

a=9 , d=6 n=8

a+(n-1)d = an

9+(8-1)6 = an

9+7×6 = an

9+42 = an

51 = an

5 0
2 years ago
Maggie was doing research for her Ph.D. in physics when a 12 mg sample of radioactive material decayed to 3 mg in 26 minutes. De
netineya [11]

The general way to work this out is to solve the general expression for
the remaining quantity versus half-life, using logarithms.  But that's not
necessary with these numbers.

Look at the numbers:

-- 3 mg is  1/4  of  12 mg.

-- 1/4  is the product of  (1/2) x (1/2).

-- So the  3 mg is what's left of  12 mg after  2  half-lives.
The  26  minutes must be two half-lives.

-- The half-life of that substance is  26/2 = <em>13 minutes</em>.

Go Maggie !

3 0
3 years ago
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