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jeka57 [31]
3 years ago
6

What is the domain of y= log_4(x+3)? all real numbers less than -3 all real numbers greater than –3 all real numbers less than 3

all real numbers greater than 3
Mathematics
1 answer:
antiseptic1488 [7]3 years ago
7 0

Step-by-step answer:

The domain of log functions (any legitimate base) requires that the argument evaluates to a positive real number.

For example, the domain of log(4x) will remain positive when x>0.

The domain of log_4(x+3) requires that x+3 >0, i.e. x>-3.

Finally, the domain of log_2(x-3) is such that x-3>0, or x>3.

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Answer:

a = 72

Step-by-step explanation:

Subtract 56 from both sides of the equation so you can isolate the variable

128-56=72

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The square root of 35.017 is between which two integers
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The square root is between 187 and 188
6 0
2 years ago
6(x+1)/5=5x-3 help please?
Korolek [52]
First, multiply each side by 5

6(x+1) = 25x-15

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4 0
3 years ago
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The value of x + y is negative, and x is a positive interger. What must bw true about y? Explain
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If x were positive, y would have to be a larger negative number.
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The dimensions of a rectangle box are consecutive integers. If the box has volume of 13,800 cubic centimeters, what are its dime
klasskru [66]
Three consecutive integers are x, x+1, x+2.
The volume of a rectangular box is the product of its three dimensions. The volume is 138000 cm³.

x(x+1)(x+2)=13800 \\
(x^2+x)(x+2)=13800 \\
x^3+2x^2+x^2+2x=13800 \\
x^3+3x^2+2x-13800=0 \\
x^3-23x^2+26x^2-598x+600x-13800=0 \\
x^2(x-23)+26x(x-23)+600(x-23)=0 \\
(x^2+26x+600)(x-23)=0 \\ 
x^2+26x+600=0 \ \lor \ x-23=0 \\ \\
1. \\
x^2+26x+600=0 \\ \\
a=1 \\ b=26 \\ c=600 \\ \Delta=b^2-4ac=26^2-4 \times 1 \times 600=676-2400=-1724 \\
\hbox{the discriminant is less than 0 so there are no real solutions} \\ \\
2. \\
x-23=0 \\
x=23 \\ \\
x+1=23+1 =24 \\ \\
x+2=23+2=25

The dimensions of the box are 23 cm x 24 cm x 25 cm.
5 0
3 years ago
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