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jeka57 [31]
3 years ago
6

What is the domain of y= log_4(x+3)? all real numbers less than -3 all real numbers greater than –3 all real numbers less than 3

all real numbers greater than 3
Mathematics
1 answer:
antiseptic1488 [7]3 years ago
7 0

Step-by-step answer:

The domain of log functions (any legitimate base) requires that the argument evaluates to a positive real number.

For example, the domain of log(4x) will remain positive when x>0.

The domain of log_4(x+3) requires that x+3 >0, i.e. x>-3.

Finally, the domain of log_2(x-3) is such that x-3>0, or x>3.

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The radius of Earth is about 3,980 miles. What expression can be used to find the approximate diameter of Earth?
Tatiana [17]
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Please help!!!!!!!!!!
Basile [38]

Answer:

1-c

2-b

3-a

Step-by-step explanation:

1. 7y=14

y=2

-7y=-14

y=2

so the equation has one solution

2. 0=0

so the equation has infinite solution

3. 0=2 false

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6 0
3 years ago
Read 2 more answers
If x =2 find the value of q in the equation 3x-4=x+q​
Effectus [21]

Step-by-step explanation:

given x=2

and the equation

3x - 4 = x + q

to find the value of q , you need to make q the subject in the equation as shown below

q= 3x-x -4

q=2x-4

but x= 2

so just substitute the value of x in the equation for the q

q = 2(2) - 4

q=4-4

q=0

therefore the value of q is 0

5 0
3 years ago
A manufacturer cuts squares from the corners of a rectangular plece of sheet metal that measures 2 inches by 7 inches (see Figur
Vladimir79 [104]

Answer:

The value of x that maximizes the volume enclosed by this box is 0.46 inches

The maximum volume is 3.02 cubic inches

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The volume of the open-topped box is equal to

V=LWH

where

L=(7-2x)\ in\\W=(2-2x)\ in\\H=x\ in

substitute

V=(7-2x)(2-2x)x

Convert to expanded form

V=(7-2x)(2-2x)x\\V=(14-14x-4x+4x^{2})x\\V=14x-14x^2-4x^2+4x^{3}\\V=4x^{3}-18x^{2} +14x

using a graphing tool

Graph the cubic equation

Remember that

The domain for x is the interval -----> (0,1)

Because

If x>1

then

the width is negative (W=2-2x)

so

The maximum is the point (0.46,3.02)

see the attached figure

therefore

The value of x that maximizes the volume enclosed by this box is 0.46 inches

The maximum volume is 3.02 cubic inches

8 0
3 years ago
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