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marusya05 [52]
3 years ago
6

Solve 3(x + 2) > x.

Mathematics
1 answer:
Georgia [21]3 years ago
5 0
3(x + 2) > x
3x + 6 > x
3x - 3x + 6 > x - 3x
6 > -2x
6/-2 < -2x/-2
-3< x
(When dividing by a negative, reverse the direction of the inequality side, reverse it EVERY time you divide by a negative)

ANSWER: -3 < x
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The standard form of a quadratic equation is ,

ax² + bx + c = 0.

And the formula to find the discriminant is b² - 4ac.

Here the first step is to change the given equation into standard form. So, add 1 to each sides of the equation. Therefore,

2x² – 9x + 2+1 = –1 + 1

2x² – 9x + 3 = 0

Next step is to compare the given equation with this equation to get the value of a, b and c.

After comparing the equations we will get a = 2, b = -9 and c = 3.

So, discriminant = b²- 4ac

=( -9)²-4 (2)(3)

= 81 - 24

= 57

So, discriminant of the given equation is 57.

57 is greater than 0 and square root of 57 will result real number.

So, the correct choice is C: The discriminant is greater than 0, so there are two real roots.

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