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In-s [12.5K]
3 years ago
15

Which of the following is the algebraic expression that best describes the sequence 3, 9, 27, 81, 243, …?

Mathematics
2 answers:
sukhopar [10]3 years ago
7 0
It's basically multiplication by 3. 3x3 9x3 27x3 etc
Phoenix [80]3 years ago
6 0
Multiply by the 3's!!!
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If u={1,2,3,4,5},A={2,4} and Beta {2,5,5}find n(AUB)​
slavikrds [6]

<em>u={1,2,3,4,5},A={2,4} and Beta {2,5,5}</em>

<em>now</em><em>,</em><em> </em><em>(AUB)</em><em>=</em><em>{</em><em>1</em><em>,</em><em>3</em><em>,</em><em>3</em><em>,</em><em>4</em><em>,</em><em>5</em><em>}</em>

<em>[</em><em>AUB</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>set</em><em> </em><em>of</em><em> </em><em>all</em><em> </em><em>elements</em><em> </em><em>of</em><em> </em><em>set</em><em> </em><em>A</em><em> </em><em>and</em><em> </em><em>set</em><em> </em><em>B</em><em> </em><em>without </em><em>any</em><em> </em><em>repetition </em><em>]</em>

<em>n</em><em>(</em><em>AUB</em><em>)</em><em>=</em><em>5</em>

<em>n</em><em>(</em><em>AUB</em><em>)</em><em>is</em><em> </em><em>the</em><em> </em><em>total</em><em> </em><em>no</em><em> </em><em>of</em><em> </em><em>elements</em><em> </em><em>in</em><em> </em><em>set</em><em> </em><em>(</em><em>AUB</em><em>)</em>

7 0
3 years ago
Can you guys help we with this question. ​​​​​​
satela [25.4K]

Answer:

40

Step-by-step explanation:

(2x+1/(2x))^5 *(2x -1/(2x))^5

= ((2x)^2 -1/(2x)^2)^5 (a+b)*(a-b) =a2-b2

= (4x^2-1/4(x)^2)^5

now

x =4x^2. ,a = 1/4(x)^2 ,n =5

we have

general term = Cr *x^r *a^(n-r)

= Cr * (4x^2)^r * (1/4(x)^2)^(n-r)

= Cr *4^r * X^2r * 1/( 4^(n-r) *x^(2n-2r)

= Cr * 4^r/4^(n-r) * x^(2r)/x^(2n-2r)

= Cr * 4(2r-n) *x(4r-2n)

now for x^2

4r-2n = 2

4r -10=2

4r =12

r = 3

now for coeff

C(5,3) * 4^(2*3-5)

5!/(3!*(5-3)!) * 4

5*4/(2*1)*4

40

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2 years ago
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Anna35 [415]
It is:

40+1+0.3+0.02=41.32



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Tamiku [17]

Answer:

the answer is 25 in this question hope it helped

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Which is equivalent to the expression 4( +5) +4x +8
Ann [662]

Answer: 13+16x

Step-by-step explanation:

Okay so I just learned how to do that haha, so if the answer is wrongdoing I'm a sorry.

I added the 8 and five, then multiplyed the 4 and the 4 then added the x on the end.

8 0
2 years ago
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