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2 years ago

6

What is cos^{-1} (0.393) [/tex]

1 answer:

alexgriva [62]2 years ago

4 0

Acos(0.393)=66.85˚
Use $cos^{-1} (0.393)$ to solve

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DedPeter [7]

Whatever is inside parentheses first [g(x)], is what you would evaluate first, then after that, you would substitute that answer into the f(x) function for EVERY "X" YOU SEE:

[2x² + 5]² + [2x² + 5] + 2

[2x² + 5]² + [2x² + 7]↓

This is your final answer. You get it?

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3 years ago

A multi-layer cake is in the shape of a right cylinder. The height of the cake is 20 centimeters, and its radius is 10 cm. If ea

gizmo_the_mogwai [7]

Answer:

There are total 5 layers.

Step-by-step explanation:

A multi-layer cake is in the shape of a right cylinder.

Height of the cake is = 20 cm

Radius is = 10 cm

Each of the cake layers has a volume of approximately 1,250 cm³.

Means, the volume of 1 cylindrical layer is 1250 cubic cm with radius as 10 cm and we have to find the height.

Volume of the cylinder is given as:

$V=\pi r^{2} h$

$1250=3.14\times(10)^{2}\times h$

$1250=314 h$

$h=\frac{1250}{314}$

h = 3.98 or approximately height of 1 layer is 4 cm.

As the cake's height is 20 cm so, there are $\frac{20}{4}=5$ layers in the cake.

Answer: There are 5 layers in the cake.

5 0

3 years ago

The tickets in a box are numbered from 1 to 15 inclusive. If a ticket is drawn at random and replaced and then a second is drawn

ludmilkaskok [199]

14/30 is the probability that the sum is even.

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2 years ago

Put the following in ascending order

Afina-wow [57]

Answer:

see explanation

Step-by-step explanation:

To be able to compare the fractions we require them to have a common denominator.

The lowest common denominator of

15, 5, 3, 2, 10, 3 is 30

Multiply the numerator/denominator of each fraction by the required value which makes the denominator 30.

denominator 15, multiply by 2

denominator 5, multiply by 6

denominator 3, multiply by 10

denominator 2, multiply by 15

denominator 10, multiply by 3

-------------------------------------------------------

$\frac{7}{15}$ = $\frac{7(2)}{15(2)}$ = $\frac{14}{30}$

$\frac{2}{5}$ = $\frac{2(6)}{5(6)}$ = $\frac{12}{30}$

$\frac{1}{3}$ = $\frac{1(10)}{3(10)}$ = $\frac{10}{30}$

$\frac{1}{2}$ = $\frac{1(15)}{2(15)}$ = $\frac{15}{30}$

$\frac{9}{10}$ = $\frac{9(3)}{10(3)}$ = $\frac{27}{30}$

$\frac{2}{3}$ = $\frac{2(10)}{3(10)}$ = $\frac{20}{30}$

----------------------------------------------------------------

Placing these in ascending order ( smallest to largest )

$\frac{10}{30}$ , $\frac{12}{30}$ , $\frac{14}{30}$ , $\frac{15}{30}$ , $\frac{20}{30}$ , $\frac{27}{30}$

----------------------------------------------------------------------

Listing the actual fractions corresponding to the equivalent fractions

$\frac{1}{3}$ , $\frac{2}{5}$ , $\frac{7}{15}$ , $\frac{1}{2}$ , $\frac{2}{3}$ , $\frac{9}{10}$

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3 years ago

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Mkey [24]

The answer is C sorry I hope this helps have a great day

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2 years ago

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