Answer:
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Step-by-step explanation:
no se weydgfds
Answer:
Well, how many were left over? Mrs. Adams has a muffin factory and made 1 million muffins. Carl ate 2/5 or 40% or 400,000 muffins, and John ate 25. 599,975 muffins were shipped for sale. That meets the stated requirements.
Hence, we have to guess there were supposed to be no muffins left over.
In that case, Mrs. Adams baked 125/3 muffins, Carl ate 2/5 of them = 50/3, leaving 75/3 = 25 for John.
Step-by-step explanation:
x muffins baked, 2/5 eaten by Carl, 3/5 left to be eaten by John, who ate 25 before running out.
3/5 x = 25
x = 25 × 5/3 = 125/3 = 41 + 2/3
Or, Start with x muffins. Carl ate 2/5 x, leaving 3/5 x. John ate 25 with zero left over. So 3/5 x = 25.
(x - 2/5 x) - 25 = 0
3/5 x = 25
x = (5/3) × 25 = 125/3.
11/18 =0.6111111. I don’t think the ! Has any meaning
Answer:
<h2>
y = -4/9</h2>
Step-by-step explanation:
Given the system of equations y = 3/2 x − 6, y = −9/2 x + 21, since both expressions are functions of y, we will equate both of them to find the variable x;
3/2 x − 6 = −9/2 x + 21,
Cross multiplying;
3(2x+21) = -9(2x-6)
6x+63 = -18x+54
collecting the like terms;
6x+18x = 54-63
24x = -9
x = -9/24
x = -3/8
To get the value of y, we will substitute x = -3/8 into any of the given equation. Using the first equation;
y = 3/2x-6
y = 3/{2(-3/8)-6}
y = 3/{(-3/4-6)}
y = 3/{(-3-24)/4}
y = 3/(-27/4)
y = 3 * -4/27
y = -4/9
Hence, the value of y is -4/9
Answer:
Where 
and 
Since the distribution for X is normal then the distribution for the sample mean is also normal and given by:
So then is appropiate use the normal distribution to find the probabilities for 
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean". The letter 
is used to denote the cumulative area for a b quantile on the normal standard distribution, or in other words: 
Solution to the problem
Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:
Where and
Since the distribution for X is normal then the distribution for the sample mean is also normal and given by:
So then is appropiate use the normal distribution to find the probabilities for
