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Romashka [77]
3 years ago
10

Aleksandra started studying how the number of branches on her tree grows over time. Every 1.51.51, point, 5 years, the number of

branches increases by an addition of \dfrac{2}{7} 7 2 ​ start fraction, 2, divided by, 7, end fraction of the total number of branches. The number of branches can be modeled by a function, NNN, which depends on the amount of time, ttt (in years). When Aleksandra began the study, her tree had 525252 branches. Write a function that models the number of branches ttt years since Aleksandra began studying her tree. N(t) =N(t)=N, left parenthesis, t, right parenthesis, equals
Mathematics
1 answer:
Alika [10]3 years ago
6 0

Answer:

52(9/7)^t/1.5

Step-by-step explanation:

The function N(t) a which models the number of branches t years after Aleksandra began studying her trees ;

Initial number of branches = 52

Increment every 1.5 years = 2/7

N(t) = Initial * (1 + r)^t

t expressed per year = t/1.5

Hence,

N(t) = 52(1 + 2/7)^t/1.5

N(t) = 52(9/7)^t/1.5

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2 years ago
What is 6.79 minus 3.95 rounded to, to the nearest half dollar
likoan [24]
$6.79 - $3.95 = $2.84. Since you’re rounding to the nearest half dollar, you’d found to $3. $2.84 is closer to $3 than $2.50

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5 0
3 years ago
Question 4: Finding a basis of the orthogonal complement Consider the matrix Find a basis of the orthogonal complement of the co
pickupchik [31]

Answer: hello your question is poorly written hence I will provide the required matrix

answer :

A = \left[\begin{array}{ccc}1&0&1\\0&1&1\\1&-1&0\end{array}\right]

Step-by-step explanation:

Given that the basis of the orthogonal complement have been provided already by you in the question I will have to provide the Matrix

The required matrix

\left[\begin{array}{ccc}1&0&1\\0&1&1\\1&-1&0\end{array}\right]

column1 = column 3 - column2

where column 3 and column 2 are the basis of the orthogonal complement of the column space of the Matrix

4 0
3 years ago
The expression x^4-9
vlada-n [284]

Answer: C

Step-by-step explanation:

By the difference of squares, x^{4}-9=(x^{2}+3)(x^{2}-3)

7 0
2 years ago
Write the equation in vertex form that has the root of -7 and has a vertex of (-1,-9)
Lapatulllka [165]

Answer:

y=\frac{1}{4}(x+1)^2-9

Step-by-step explanation:

Method 1

we know that

The equation of a vertical parabola in vertex form is equal to

y=a(x-h)^2+k

where

a is the leading coefficient

(h,k) is the vertex

we have

(h,k)=(-1,-9)

substitute

y=a(x+1)^2-9

Remember that

one root is (-7,0)

substitute and solve for a

0=a(-7+1)^2-9

0=a(-6)^2-9

0=36a-9

a=\frac{1}{4}

therefore

y=\frac{1}{4}(x+1)^2-9

Method 2

I use the fact that the roots are the same distance from the vertex

the distance from the given root to the vertex is equal to

6 units

so

If one root is x=-7

then the other root is

x=-1+6=5

The general equation of the quadratic equation is equal to

y=a(x+7)(x-5)

we have the vertex (-1,-9)

substitute the value of x and the value of y and solve for a

-9=a(-1+7)(-1-5)

-9=a(6)(-6)

-9=-36a

a=\frac{1}{4}

y=\frac{1}{4}(x+7)(x-5)

so

Expanded the equation, complete the square and rewrite as vertex form

7 0
3 years ago
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