The number of different topping combination illustrates combination
Ross have 6 different topping combination to select from
<h3>The number of different combination</h3>
The given parameters are:
Extra toppings, n = 4
Toppings to select, r = 2
The number of extra topping that Ross can select is then calculated using the following combination formula
Toppings = nCr
This gives
Toppings = 4C2
Evaluate the combination expression
Toppings = 6
Hence, Ross have 6 different topping combination to select from
Read more about combination at:
brainly.com/question/11732255
I think that you are mistaking the memory tool for something else
or a math book is trying to make math cute by calling them 'socatoa joe' and 'mr. pi' and such
anyway, SOH, CAH, TOA is the way to remember
Sine=oposite/hypotonuse
Cosine=adjacent/hypotonuse
Tangent=oposite/adjacent
(oposite side=side oposite the angle
adjacent is the side touching the angle that is not they hypotonuse
and of course the hypotonuse is the longest side aka, side oposite right angle)
Answer: Both A, and C
Step-by-step explanation:
The answer to the first system of equations (2x+2y=16) would be
x=3 and y=5 ( 3x-y=4 )
Which means we have to find out which of the other equations has an x value of 3, and a y value of 5.
If A is 2x+2y=16, then x=3 and y=5
6x-2y=8
If B is x+y=16, then x=5 and y=11
3x-y=4
If C is 2x+2y=16, then x=3 and y=5
6x-2y=8
If D is 6x+6y=48 , then x=-2 and y=10
6x+2y=8
Both A and C are equal to the first system of equations, which means they are both correct answers.
Yes I done it happy new year and a happy evening wish you a happy Christmas
