LHS ⇒ RHS:
Identities:
[1] cos(2A) = 2cos²(A) - 1 = 1 - 2sin²(A)
[2] sin(2A) = 2sin(A)cos(A)
[3] sin(A + B) = sin(A)cos(B) + cos(A)sin(B)
[4] cos(A + B) = cos(A)cos(B) - sin(A)sin(B)
cos(x) - cos(x + 2Θ)
= cos(x) - (cos(x)cos(2Θ) - sin(x)sin(2Θ)) [4]
= cos(x) - cos(x)(1 - 2sin²(Θ)) + sin(x)(2sin(Θ)cos(Θ)) [1] [2]
= cos(x) - cos(x) + 2sin²(Θ)cos(x) + 2sin(Θ)sin(x)cos(Θ)
= 2sin²(Θ)cos(x) + 2sin(Θ)sin(x)cos(Θ)
= 2sin(Θ)(sin(Θ)cos(x) + sin(x)cos(Θ))
= 2sin(Θ)sin(x + Θ)
Answer:
C) 3930.4 in3
Step-by-step explanation:
volume of a cube = length x width x height
v=17 x 17 x 17 = 4913
4913 x 80% = 3930.40
Answer:
m<HIG and alternate interior angles
HOPE IT HELPS
G(x) would involve a translation left 1 and up 1.
g(x) is written in vertex form, which is
g(x) = a(x-h)²+k, where (h, k) is the vertex. Since
g(x) = 4(x-8)²+9, the vertex is at (8, 9). Comparing this to the vertex of f(x), which is at (9, 8), it is left 1 and up 1.
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