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egoroff_w [7]
3 years ago
6

Five cans for six dollars or eight cans for cans $10

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
5 0
If this is for a better deal if you made the prices the same so instead of 5 for six itd be 50 for $60 and 8 for $10 would be 48 for $60 obviously 5 for 6 is the best choice. thats just how i was taught i hoped this helps 

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The sine of 49° is equal to the cosine of what angle?
Digiron [165]
Sinα=cos(90-α)  this is an identity which you need to know...

in this case:

sin49°=cos41°
6 0
3 years ago
The probability that Barry Bonds hits a home run on any given at-bat is 0.16, and each at-bat is independent.
serious [3.7K]

Answer:

a) 0.0797 = 7.97% probability that the next home run will be on his fifth at-bat.

b) The expected number of at-bats until the next home run is 6.25.

Step-by-step explanation:

For each at bat, there are two possible outcomes. Either it is a home run, or it is not. The probability of an at bat resulting in a home run is independent of any other at-bat, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that Barry Bonds hits a home run on any given at-bat is 0.16

This means that p = 0.16

Part A: What is the probability that the next home run will be on his fifth at-bat?

0 on his next 4(P(X = 0) when n = 4)

Home run on his 5th at-bat, with 0.16 probability. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{4,0}.(0.16)^{0}.(0.84)^{4} = 0.49787136


0.49787136 *0.16 = 0.0797.

0.0797 = 7.97% probability that the next home run will be on his fifth at-bat.

Part B: What is the expected number of at-bats until the next home run?

The expected number of trials for n successes is given by:

E = \frac{n}{p}

In this question, n = 1, p = 0.16. So

E = \frac{1}{0.16} = 6.25

The expected number of at-bats until the next home run is 6.25.

6 0
3 years ago
I need help with this problem
Sergio039 [100]
The answer is 57765363535366355336
6 0
3 years ago
Read 2 more answers
Harold Wagner pays a $325.00 premium annually. This represents 40% of the total premium. The rest of the premium is paid by his
tigry1 [53]

Answer:

a). The company's percentage=60%

b). The total premium=$812.50

c). The company's payment=$487.50

Step-by-step explanation:

a).

The total premium can be expressed as;

T=H+R

where;

T=proportion of total premium

H=proportion paid by Harold Wagner

R=remaining proportion

In our case;

T=100%

H=40%

R=r

replacing;

100%=40%+r

r=100%-40%

r=60%

The company's percentage=60%

b).

The total premium, if 40%=$325.00

Let total premium be=t

40% of t=325

(40/100)×t=325

0.4 t=325

t=325/0.4

t=$812.50

The total premium=$812.50

c).

The company's payment=60% of total premium

The company's payment=(60/100)×812.5

The company's payment=$487.50

5 0
3 years ago
How do you solve for a g=ca
erastova [34]
g=ca\\
a=\dfrac{g}{c}
7 0
3 years ago
Read 2 more answers
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